Oh, isn't that a delightful sequence! Let's see, we start with 7, then add 34 to get 41, then subtract 29 to get 12, add 70 to get 82, subtract 29 to get 53, so following that pattern, the next numbers would be adding 70 to 24, which gives us 94, then subtracting 29 to get 65, and finally adding 70 to get 135. Isn't that just lovely?
According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid. It is, therefore, possible to find a rule such that any three number of your choice can follow the given ones.
In this case the simplest polynomial fit is obtained by
Un = (219x5 - 3885x4 + 25695x3 - 78015x2 + 107026x - 50760)/40 and, accordingly, the next three numbers are 1048, 5789 and 19179.
The next three numbers in the sequence are 23, 25, and 27.
The first thing to notice is that all the numbers in the sequence are square numbers. 25=5x5 36=6x6 49=7x7 64=8x8 81=9x9 So the next three numbers to be squared are 10, 11 and 12. 10x10=100 11x11=121 12x12=144 Thus, the next three numbers in the sequence are 100, 121, 144 The equation for the sequence is (n+4)2
Each number in the sequence is 8 times the preceeding number so the next three numbers would be... 204.8, 1638.4 and 13107.2
They are a sequence of odd numbers. The next three in the sequence would be 17,19 & 21
Well, judging by the sequence of numbers, the pattern would be to subtract one more than the last time from each new number. Meaning 33-1=32 then 32-2=30 then 30-3=27. The next three numbers would be 27-4=23 and 23-5=18 and finally 18-6=12. So 23 18 and 12 would be the next three numbers in sequence.
There are no numbers specified therefore this question is unanswerable.
One number, such as 23266992 does not for a sequence.
Assuming the sequence of numbers declines by 5 each time, the next three numbers would be 40, 35 and 30.
It appears as if the pattern is doubling, therefore the next three numbers are 16, 32, and 64.
There are no numbers specified therefore this question is unanswerable.
The next three numbers in the sequence are 23, 25, and 27.
The first thing to notice is that all the numbers in the sequence are square numbers. 25=5x5 36=6x6 49=7x7 64=8x8 81=9x9 So the next three numbers to be squared are 10, 11 and 12. 10x10=100 11x11=121 12x12=144 Thus, the next three numbers in the sequence are 100, 121, 144 The equation for the sequence is (n+4)2
25 36 49 64 81 100 121 144
Each number in the sequence is 8 times the preceeding number so the next three numbers would be... 204.8, 1638.4 and 13107.2
Should there be a 16 in there somewhere? If so next three are 36, 49 and 64...
18 34 66
100 200 20