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According to Wittgenstein's Finite Rule Paradox every finite sequence of numbers can be a described in infinitely many ways and so can be continued any of these ways - some simple, some complicated but all equally valid. It is, therefore, possible to find a rule such that any three number of your choice can follow the given ones.

In this case the simplest polynomial fit is obtained by

Un = (219x5 - 3885x4 + 25695x3 - 78015x2 + 107026x - 50760)/40 and, accordingly, the next three numbers are 1048, 5789 and 19179.

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34

Lvl 2

94 - 65 - 36

Lvl 1

94,65,36

Q: What are the next three numbers in the sequence 7-41-12-82-53-24?

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1, 4,9, 16, 25, 36,49 this is the next three sequence po

The next three numbers in the sequence are 23, 25, and 27.

The first thing to notice is that all the numbers in the sequence are square numbers. 25=5x5 36=6x6 49=7x7 64=8x8 81=9x9 So the next three numbers to be squared are 10, 11 and 12. 10x10=100 11x11=121 12x12=144 Thus, the next three numbers in the sequence are 100, 121, 144 The equation for the sequence is (n+4)2

Each number in the sequence is 8 times the preceeding number so the next three numbers would be... 204.8, 1638.4 and 13107.2

They are a sequence of odd numbers. The next three in the sequence would be 17,19 & 21

Related questions

There are no numbers specified therefore this question is unanswerable.

One number, such as 23266992 does not for a sequence.

1, 4,9, 16, 25, 36,49 this is the next three sequence po

Assuming the sequence of numbers declines by 5 each time, the next three numbers would be 40, 35 and 30.

It appears as if the pattern is doubling, therefore the next three numbers are 16, 32, and 64.

There are no numbers specified therefore this question is unanswerable.

The next three numbers in the sequence are 23, 25, and 27.

The first thing to notice is that all the numbers in the sequence are square numbers. 25=5x5 36=6x6 49=7x7 64=8x8 81=9x9 So the next three numbers to be squared are 10, 11 and 12. 10x10=100 11x11=121 12x12=144 Thus, the next three numbers in the sequence are 100, 121, 144 The equation for the sequence is (n+4)2

25 36 49 64 81 100 121 144

Each number in the sequence is 8 times the preceeding number so the next three numbers would be... 204.8, 1638.4 and 13107.2

Should there be a 16 in there somewhere? If so next three are 36, 49 and 64...

11, -10, 9