2 x 2 x 5 = 20
2 x 3 x 5 = 30
2 x 5 x 5 = 50
2 x 5 x 7 = 70
Three of the bits are already determined. That leaves 5 .25 = 32
70
The prime factors of 100 are: 2 and 5
100
5 is the largest prime factor of 100. Prime factors of 100 are 2 x 2 x 5 x 5
Prime factorization of 40 = 2x2x2x5 Prime factorization of 100 = 2x2x5x5
64 and 96 have the longest prime factorizations in that range. If you're asking about distinct prime factors, quite a few are tied with three.
1 is not a prime number, so it wouldn't be present in any prime factorization. Prime numbers don't really have factorizations, that is, the factorization is the number itself. There are prime numbers greater than 100.
The prime factors of 100 are 2 and 5 Prime factorization of 100: 2 x 2 x 5 x 5 or 2^2 x 5^2
The three prime numbers after 100 are: 101 103 107
Neither. According t the fundamental theorem of arithmetic (also called the unique prime factorisation theorem), any integer has one and only one prime factorisation. In any case, both numbers have 4 prime factors.
79, 19, 2
smallest 3-digit prime is 101. 100 is not a prime number (very obviously)
31 + 67 + 2
83, 89, and 97
2, 31 and 67 if you add them.
63, 89, 97