The reactants in the equation are potassium iodide (KI) and lead(II) nitrate (Pb(NO3)2).
Lead(II) iodide or plumbous iodide
lead acetate
This is called lead(II) iodide.
The balanced equation for the reaction between lead(II) nitrate (Pb(NO3)2) and sodium iodide (NaI) to form lead(II) iodide (PbI2) and sodium nitrate (NaNO3) is: Pb(NO3)2 + 2NaI -> PbI2 + 2NaNO3
Pbl2
The chemical name for PbI2 is lead (II) iodide.
There are 3 atoms in PbI2 - one lead (Pb) atom and two iodine (I) atoms.
PbI2, lead(II) iodide, is an ionic compound. Lead(II) is a metal and iodide is a non-metal, so they typically form ionic bonds.
The reaction that occurs is a double displacement reaction where lead(II) nitrate and potassium iodide switch partners to form solid lead(II) iodide and potassium nitrate solution. This reaction can be represented by the equation Pb(NO3)2 + 2KI -> Pbl2 + 2KNO3.
PbI2 is the chemical formula for lead (II) iodide, a yellow crystalline compound. It is commonly used in organic synthesis and as a catalyst in certain chemical reactions. Lead (II) iodide is also used as a detector material for gamma rays and X-rays.
When potassium iodide is mixed with lead nitrate, a double displacement reaction occurs. The products formed are lead iodide and potassium nitrate. Lead iodide is a yellow precipitate that forms during the reaction.