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What are the solutions to the simultaneous equations of x -2y equals 1 and 3xy -y squared equals 8 showing all appropiate work with answers?
If: x-2y = 1 and 3xy -y^2 = 8
Then: x = 1+2y and 3(1+2y)y -y^2 = 8
Hence: 3y+6y^2 -y^2 = 8 => 5y^2 +3y -8 = 0
Solving the above quadratic equation: y =1 or y = -8/5
Solutions by substitution are: when y=1 then x=3 and when y=-8/5 then x=-11/5
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