0
You should write this in polar notation, i.e., with an angle. Visualize the imaginary axis as being 90° from the real axis. Thus, 6i = 6 (angle) 90°, that is, it has an absolute value of 6, and is at an angle of 90°. The main square root of that is equal to the square root of 6 (angle) 45°. To get the other square root, add 180° degrees to that angle (same absolute value). Now, use your calculator's polar-->rectangular conversion to separate that into real and imaginary parts (if that's what you want).
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
What is The square root of 25-2times the square root of -36 plus the square root of four - the square root of 121?
Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i
What is the square root of negative 36?
6i
Square root of -36?
The square root of -36 is 6 i
What keeps a square from moving?
Concrete.
What is the equivalent form of 10 plus 6i and 7 plus 2i?
10 + 6i and 7 + 2i = 10 + 6i + 7 + 2i = 17 + 8i
What are two square roots of -36?
There are no real numbers, only in the imaginary field they are -6i and 6i where i is the imaginary square root of -1.
What is The square root of 25-2times the square root of -36 plus the square root of four - the square root of 121?
Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i
What is 6i multiplied by the square root of 5?
6i*sqrt(5) is irreducable and is about 13.4164i
Square root over -36?
6i is the answer to square root -36
What is the square root of negative 36?
6i
Square root of -36?
The square root of -36 is 6 i
What is the square root of -36 in simplest radical form?
6i
How do you find a 4th degree polynomial with zeros x equals 4 x equals -3 and x equals 6i?
There are only three roots given so, in general, there is no unique answer. However, if it is a real polynomial, then its complex roots must come in conjugate pairs. Then 6i is a root implies that -6i is a root. So the polynomial is (x - 4)(x + 3)(x + 6i)(x - 6i) = (x2 - x - 12)(x2 + 36) = x4 + 36x2 - x3 - 36x - 12x2 - 432 = x4 - x3 + 24x2 - 36x - 432
In algebra what is the square root of -36?
6i which also means 6 as an imaginary number.
How do you write the square root of -36?
6i the square root of a negative number makes an imaginary number (i) and the square root of 36 is 6.
What is the square root of 11449?
The square roots are -1.07 and +1.07The square roots are -1.07 and +1.07The square roots are -1.07 and +1.07The square roots are -1.07 and +1.07
How do you get the solution to 6 divided by the square root of -10?
16
