5k - 2*(h - 8k) = 5k - 2h + 16k = 21k - 2h
k = 2 7 + (5 x 2) = 17 (8 x 2) + 1 = 17
9/8k + 6/6 = (9 + 8k)/8k9/8k + 6/6 = (9 + 8k)/8k9/8k + 6/6 = (9 + 8k)/8k9/8k + 6/6 = (9 + 8k)/8k
16k
each mile's 1,600 metres. 8k = 8,000 metres. therefore, there's 5 miles in 8k.
k = 8k + 28Subtract '8k' from each side of the equation:-7k = 28Divide each side by '-7' :k = -4
8k-7-3k=1? 5k-7=1 5k=8 k=8/5 8k-7 =-3k+1 11k-7=1 11k=8 k=8/11 8k-7-3k+1=0 5k-6=0 5k=6 k=6/5=1.2 depends on where = sign is in the question
5k + 7 + 3k can be simplified into 8k + 7
It is 8k+7 simplified
15015 :)
The range of a college XC meets can range from a 5K (2.98-3.1 miles), 8K (4.8-5 miles), or 10K (5.9-6.1 miles). Typically 5K (3.1 miles) or 6K (3.8) for women and 8K (4.8) for men.
Any rational number of the form 5k/8k where k is an integer is equivalent.
k = 2 7 + (5 x 2) = 17 (8 x 2) + 1 = 17
5k-7k for a 100,000 mile VW Golf so expect a 30,000-60,000 mile VW Golf to be around 8k-10k
9/8k + 6/6 = (9 + 8k)/8k9/8k + 6/6 = (9 + 8k)/8k9/8k + 6/6 = (9 + 8k)/8k9/8k + 6/6 = (9 + 8k)/8k
Little over 3 miles, little under 5, little over 6, about 9 and a third.
There is cross country running, which is long distance running (4k, 5k, 8k 10k) k is kilometers. and there is also cross country skiing, which is long distance skiing.
The Hal Higdon training program involves distance race training for novice, intermediate and advanced runners for 5K, 8K, 15K, and half marathon runs.