Solving the above simultaneous equations by means of the elimination method works out as x = 2 and y = 3
2X + 6Y = 12 3X + 9Y = 18 try elimination - 3(2X + 6Y = 12) 2(3X + 9Y = 18) - 6X - 18Y = - 36 6X + 18Y = 36 ================= I will say this system is dependent and an infinite number of solutions can be found.
6-3x+12=0 6+12-3x=0 18-3x=0 18=3x x=6
3x-3x equal = 0
3x
3x + 2 = -10 3x = -12 x = -4
4x+6-7x+9=18-3x+15=18-3x=3x=-1
-3x + (-18) = 2x + 7 +18 +18 -3x = 2x +25 -2x -2x -5x = 25 ----- ----- -5 -5 x=-5 *------- equals a division line
No.
x^2 + 3x + 7 = 6x + 18 x^2 - 3x - 11 = 0
you mean: x+3x+3=x+18 so x=5
1
-2
-2
(-1, 5)
(-1, 5)
3x + 5 = 6x + 23 -3x = 18 x = -6
-3x+7=2x-18 ---> 7+18=2x-3x ----> 25=5x ----> x=5