Let the first number be x, the second x + 1, and the third x + 2. So,
x + x + 1 + x + 2 = 60
3x + 3 = 60 subtract 3 to both sides;
3x = 57 divide by 3 to both sides;
x = 19
x + 1 = 19 + 1 = 20
x + 2 = 19 + 2 = 21
Thus the numbers are 19, 20, and 21.
The numbers are 59, 60 and 61. Also, 58, 60 and 62.
Consecutive whole numbers will have an odd sum. Consecutive odd numbers, or consecutive prime numbers, will be 29 and 31.
121
58, 60 and 62.
There are no such four whole numbers that do, but 131/2 + 141/2 + 151/2 + 161/2 = 60.
The numbers are 59, 60 and 61. Also, 58, 60 and 62.
19, 20, 21
Consecutive whole numbers will have an odd sum. Consecutive odd numbers, or consecutive prime numbers, will be 29 and 31.
3 x 4 x 5 = 60 The three consecutive numbers are 3, 4, and 5.
121
The numbers are 59, 60 and 61.
To find three consecutive numbers that multiply to 60, you can start by estimating the cube root of 60, which is about 3.9. The three consecutive integers around this value are 3, 4, and 5. Multiplying these together: (3 \times 4 \times 5 = 60). Thus, the three consecutive numbers are 3, 4, and 5.
Their sum is -12
Oh, what a happy little problem we have here! If we have three consecutive numbers, we can call them x, x+1, and x+2. When we add these together and set it equal to 175, we get 3x + 3 = 175. By solving this simple equation, we find that the three consecutive numbers are 58, 59, and 60.
60/3-1, 60/3 and 60/3+1 that is, 19, 20 and 21.
58, 60 and 62.
There are no such four whole numbers that do, but 131/2 + 141/2 + 151/2 + 161/2 = 60.