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Let the first number be x, the second x + 1, and the third x + 2. So,

x + x + 1 + x + 2 = 60

3x + 3 = 60 subtract 3 to both sides;

3x = 57 divide by 3 to both sides;

x = 19

x + 1 = 19 + 1 = 20

x + 2 = 19 + 2 = 21

Thus the numbers are 19, 20, and 21.

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15y ago
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Q: What are three consecutive numbers that add up to 60?
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