can I have the awnser
4 and 9
9 + 16 = 25
They are: 16 amd 9
4 and 9
Algebraically, this is written as a^(2) + b^(2) = h^(2) (The Pythagorean eq'n).
Algebraically, this is written as a^(2) + b^(2) = h^(2) (The Pythagorean eq'n).
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when you subtract one square number with another the answer is 16 what are the two numbers
4 and 9
The square numbers are: 16-4 = 12
Another square number.
The numbers are 9 and 25. (If you allow zero as a square 02 = 0, then 0 and 16 are another pair.)
16 and 4
Let the squares be 'x' & 'y' Hence x^(2) - y^(2) = 7 Factor ( x - y)( x + y) = 7 Since '7' is a prime number, we need two number that add to '7' and subtract to '1'. They are 3, & 4 Hence (4 - 3) ( 4 + 3) = 1(7) = 7
1 and 36
Yes
That isn't possible.