What are two consecutive odd numbers whose product is 783?

Answer 1

Let the smaller number be n then the other number is (n + 2).

Then, n(n + 2) = 783

n2 + 2n = 783......which can be rearranged as : n2 + 2n - 783 = 0

This can be factored : n2 + 2n - 783 = (n + 29)(n - 27) = 0

The solution that concerns us is when n is positive. This occurs when, n - 27 = 0 : n = 27.

Then the two consecutive odd numbers are 27 and 29.