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In an isosceles triangle does the median to the base bisect the vertex angle?
In the diagram, ABC is an isoscels triangle with the congruent sides and , and is the median drawn to the base . We know that ∠A ≅ ∠C, because the base angles of an isosceles triangle are congruent; we also know that ≅ , by definition of an isosceles triangle. A median of a triangle is a line segment drawn from a vertex to the midpoint of the opposite side. That means ≅ . This proves that ΔABD ≅ ΔCBD. Since corresponding parts of congruent triangles are congruent, that means ∠ABD≅ ∠CBD. Since the median is the common side of these adjacent angles, in fact bisects the vertex angle of the isosceles triangle.
Does the angle bisector of the vertex angle of an isosceles triangle divides the triangle into two congruent?
Only if the vertex angle being bisected is between the sides of equal length will the result be two congruent triangles.
What is a counter example for the statement congruent angles are always vertical angles?
Vertical angles must necessarily be congruent, however congruent angles do not necessarily have to be vertical angles. An example of congruent angles which are not vertical angles are the 3 interior angles of an equilateral triangle. These angles do not share the same vertex yet they are congruent.
What is the measure of the vertex angle of an isosceles triangle if the base angles measure 56 degrees?
If each base angle is 56°, then the vertex angle is 68°.If both base angles combined total 56°, then the vertex angle is 124°.
What is the measure of each base angle of an isosceles triangle if its vertex angle measures 40 degrees and its 2 congruent sides measure 25 units?
Length of sides is irrelevant. Angles are ((180 - 40)/2) ie 70o
