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What are you if you are a two digit number between 10 and 40 and the sum of all your divisors?
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∙ 12y ago
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∙ 12y ago
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What is a two-digit number between 10 and 40 which is th sum of all its divisors?
28 is such a number.
What am I if I am a two digit number between 10 and 40 and the sum of all my divisors?
15
List all abundant numbers 1 to 49?
An abundant number is any natural number (starting from 1) that is less than the sum of all its divisors excepting itself (the set of "all its divisors excepting itself" is also known as the set of its "proper divisors"). The lowest abundant number is twelve, and the first nine (all of those between one and fourty-nine, inclusive) are: 12 18 20 24 30 36 40 42 48
What is dividers for math?
Do you mean divisors? If you are, then a divisor is the number that is by divided. That's really all there is to say about divisors. I'm very sorry if this doesn't help.
What are 2 almost perfect numbers between 5 and 20?
Perfect numbers are numbers where all the factors add to that number. For example 6's factors are 1,2, and 3 and 1+2+3=6. Therefore the next perfect number isn't until 28 which is 1,2, 4, 7, 14 where 1+2+4+7+14= 28 An almost perfect number is a number which, when adding all of its proper divisors (all divisors except himself), gives you one less, or one more then the number itlself. Up to now all known almost perfect numbers are 2^n. So to answer your question, the 2 almost perfect numbers between 5 and 20 are 8 and 16. Divisors of 8: 1,2,4 -----> 1+2+4=7 Divisors of 16: 1,2,4,8 -----> 1+2+4+8=15
What is a two-digit number between 10 and 40 which is th sum of all its divisors?
28 is such a number.
What am I if I am a two digit number between 10 and 40 and the sum of all my divisors?
15
What are some of the mathematical properties of the number 925?
925 is a number divisible by 5, as its last digit is a 5. It is an odd number. Its divisors are 5, 5, and 37, also all odd numbers. It is a three-digit number.
What is the sum of all the whole number divisors of 8?
15
Is the number 14 a abundant perfect or deficient number?
14 is deficient. It is less than the sum of it's divisors. In mathematics, a deficient number or defective number is a number n for which σ(n) < 2n. Here σ(n) is the sum-of-divisors function: the sum of all positive divisors of n, including n itself Proof.. divisors of 14 are 1,2, and 7 and 14. Now, 2n=28 and and the sum the all the divisors including 14 is 24<28
List all abundant numbers 1 to 49?
An abundant number is any natural number (starting from 1) that is less than the sum of all its divisors excepting itself (the set of "all its divisors excepting itself" is also known as the set of its "proper divisors"). The lowest abundant number is twelve, and the first nine (all of those between one and fourty-nine, inclusive) are: 12 18 20 24 30 36 40 42 48
What are all of the divisors of 100 between 1 and 10 that are integers or numbers with a max of two decimals ie 1.25?
Divisors are whole numbers. The divisors of 100 between 1 and 10 are 1, 2, 4, 5 and 10.
draw a flowchart to read a number in and print all its divisors?
Hi
Are all prime numbers imperfect?
yes. The only divisors of a prime number are itself and 1. Without counting the prime number, the sum of it's divisors is always 1.
What is the result of symbol number 2085004?
There is no result: all you have is a 7-digit number.There is no result: all you have is a 7-digit number.There is no result: all you have is a 7-digit number.There is no result: all you have is a 7-digit number.
What is dividers for math?
Do you mean divisors? If you are, then a divisor is the number that is by divided. That's really all there is to say about divisors. I'm very sorry if this doesn't help.
What is the perfect number and what is the perfect number after six?
A perfect number is a number, which, when adding all of its proper divisors (all divisors except himself) give the number itself Divisors of 6: 1,2,3 ------>1+2+3=6 The next proper number is 28 Divisors of 28:1,2,4,7,14 -------> 1+2+4+7+14=28 All perfect numbers found so far are found using this formula: 2^(p-1)*((2^p)-1), where p, and ((2^p)-1) are prime numbers
