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Conjecture: the sum of two even integers is always an even integer.

Suppose M and N are two even integers.

M is even and so it is divisible by 2 without remainder. That is to say, there is some integer X, such that M = 2X.

Similarly, N = 2Y for some Y.

Then M + N = 2X + 2Y

=2*(X + Y) due to the distributive property of multiplication over addition of integers.

And, by the closure of the set of integers under addition, X+Y is an integer.

Therefore, M + N is equal to 2 times an integer and therefore it is an even integer.

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