Well, if 4cm is 12 km, and there are five 4cm in 20cm, 12*5=60, so:
There are 60km in a distance of 20cm on a map with a scale of 4cm to 12km.
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The height of a ball is 12 m A scale model is made of a hall The height of the scale model of the hal is 30 cm Express the scale of the model in the form 1n?
1 mile = 1760 yards 1 yard = 3 feet 1 foot = 12 inches. Therefore 1 mile = 1760*3*12 = 63360 inches. 1/4 of a mile = 63,360/4 = 15840 inches. Therefore 1 inch is representing 15,840 inches and the scale is 1:15,840
The distance between points can be calculated using Pythagoras: distance = √(change_in_x² + change_in_y²) → distance = √((4 - 10)² + (36 - 12)²) → distance = √((-6)² + (24)²) → distance = √(36 + 576) → distance = √612 → distance = 6 √17 ≈ 24.74 units.
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In this case you have a map with a scale of 1:250000, meaning 1 map unit represents 250000 units on the actual ground. Since the distance on the map is 50 cm(centimeters) we calculate the distance as follows Distance on the ground = distance on the map * the scale 50 cm * 250000 giving us 12 500 000. Therefore, the distance on the ground is 12 500 000 centimeters.
if a map show the straight line distance between two cities as 3 and one half centimeters and the map scale show that 1 centimeter equals 100 kilometers what would the actual distance be ?
??
Yes.
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On that scale... 6 inches !
1,000.
Square side 3cm. Rectangle 2cm x 4cm. Equilateral triangle side 4cm.
It would represent 6 inches!
6 inches
it should be about 4cm long
The area is 12 cm2.