Their common factors are 1 and 7 .
2 56 4 28 8 14
2235
1, 2, 4, 7, 8, 14, 16, 28, 56, 112.
2 divides 4 into 2 with no remainder, 3 divides 6, 12 divides 36, 4 divides 12, there are way to many to name them allIs called a factor.
7.
1, 2, 7 and 14.
42 divided by 14 equals 3
1 and 7.
Their common factors do that. The common factors of 7 and 14 are 1 and 7.
1 2 7 14 49 and 98.
A "divisor" means it evenly divides the number in question, so no: 64/14 = 4.57142857...
1, 2, 7 and 14 all divide into both 14 and 84, without leaving a remainder.
since 14 = 14 x 1 and 56 = 14 x 4 the answer is 14, since it divides evenly into both and clearly nothing larger will.There is a clever algorithm that can help you work this out in the general case:GCD(14, 56) = GCD(14, 56 - 14) = GCD(14, 42)This step (subtract the smaller from the larger) relies on the fact that any number that divides both 14 and 56 also divides 56 - 14.Repeat this:GCD(14, 42) = GCD(14, 42 - 14) = GCD(14, 28)GCD(14, 28) = GCD(14, 28 - 14) = GCD(14, 14)which is clearly 14.This is called Euclid's Algorithm.
Their common factors are 1 and 7 .
The number is 14.
2 56 4 28 8 14