If you multiply current by time, you get electric charge. In this case, because of the "milli" prefix for the current, you would also get "milli" in the answer, that is, millicoulomb.
1000
Get a and b // where a and b are 2 numbers taken from the user Set Ma to a // Ma is the multiple of a Set Mb to b // Mb is the multiple of b While Ma<>Mb //(condition is that Ma not equal Mb) { if (Ma > Mb) then // finding which multiple is smaller Set Mb to Mb + b // we add to the smaller multiple the input value Else Set Ma to Ma + a End if } Print "the LCM of the numbers is" + Ma
My mother - ma mère
Well it depends on what you are using for a pulley the mechanical advantage is equal to the number of ropes lifting the object such as if you have one pulley the MA (mechanical advantage) is equal to 1 if you have two pullies the MA is 2 if you are using a lever such as a seesaw you have to move the fulcrum as close to the object being lifted and have to longest possible input arm. If you modify a seesaw a 60 pound child can lift a 200 pound adult. That is about all i know hope it helps if you are using a different simple machine or need more help email me at : icecbejohn@yahoo.com
The ideal MA is 47.
20
0.1 A = 100 mA
A (amperes) is a unit of electric current. To convert milliamperes (mA) to amperes (A), you divide by 1,000. Therefore, 100 mA is equal to 0.1 A.
To convert 4.5 amps to milliamps (mA), you multiply by 1000 since 1 amp is equal to 1000 milliamps. Therefore, 4.5 amps is equal to 4500 milliamps.
To state the obvious- 1000 mA is 10x the amount of 100 mA 1 A = 1000 mA therefore 100 mA = 0.1 A
ma stands for milliamp. The prefix 'milli is equivalent to .001 So 1 amp would be 1000 milliamps and 20 milliamps would be .02 amps
If you are talking about 4 mA = 0% and 20 mA = 100% then the formula would be a linear equation: y=mx + b y=6.25(x) - 25 y= percentage x=mA ouput So for example put 4 mA in place of x and you get 0% for y and if you use 20 mA in place of x you get 100% for y. You can rewrite the equation if only Percent input is known to find mA output it would be X= (Y + 25)/6.25 this way you input the percent in for (Y) and you have the mA output for X
50 milliamps (mA) is equal to 0.05 amps.
Following Too Closely V.T.L. Sec. 1129Passing Red LightV.T.L. Sec. 1111dPassing Stop SignV.T.L. Sec. 1172Unsafe Lane ChangeV.T.L. Sec. 1128Failure To YieldV.T.L. Sec. 1140, 1141, 1142, 1143Improper PassingV.T.L. Sec. 1124Failure To Obey Traffic Control DeviceV.T.L. Sec. 1110(a)
The 4-20 ma is used more often in analog signaling than 0-20 ma because sufficient power dissipation. The hence is the upper rage and was reduced to 20 ma.
To calculate the percent signal from a given current, you typically need a reference value, often the maximum current for a 100% signal. Assuming a common reference maximum of 20 mA (used in many industrial applications), you can calculate the percent signal as follows: [ \text{Percent Signal} = \left( \frac{11.3 , \text{mA}}{20 , \text{mA}} \right) \times 100 = 56.5% ] Thus, an 11.3 mA signal corresponds to approximately 56.5%.
% / Sqrt output mA / Non square output mA 0% / 4 / 4 10% / 9.059644256 / 5.6 20% / 11.15541753 / 7.2 25% / 12 / 8 30% / 12.76356092 / 8.8 40% / 14.11928851 / 10.4 50% / 15.3137085 / 12 60% / 16.39354671 / 13.6 70% / 17.38656042 / 15.2 75% / 17.85640646 / 16 80% / 18.31083506 / 16.8 90% / 19.17893277 / 18.4 100% / 20 / 20 if u want to find mA at x% Then let Y= sq. rt(x/100) now u can to find mA of Y directly i.e mA= Y*100*.16+4 thats the mA for sq. of x eg: you want to find mA at 49% at a range of 0 to 300 cubic.meter/hr (or anything) then Y= sq.rt (49/100) =0.7 mA---> 0.7*100*.16+4 = 15.2 mA