8-h
A number h increased by i.e. added to itself = h + h =2h
The algebraic expression for "3 more than a number" can be written as x + 3, where x represents the unknown number. In this expression, the variable x is being increased by 3. This expression can be simplified further if needed, but the basic form is x + 3.
When you divide a number or variable "h" by 4, you are essentially splitting "h" into four equal parts. This can be represented as h/4. The quotient of this division operation would depend on the value of "h." If "h" is a specific number, you would perform the division operation to find the exact result.
H
Well, the ten's place is where the [ 7 ] is, so that is the number that will change. Because the [ 8 ] is larger than 4, the number will increase. 78 will turn to 80. 80
y = h + 8
Let the number of hundreds be represented as ( h ). According to the problem, the number has 3 hundreds more tens than hundreds, which gives us ( t = h + 3 ) for tens. It also states there is 1 more one than hundreds, leading to ( o = h + 1 ) for ones. Therefore, the number can be expressed as ( 100h + 10(h + 3) + (h + 1) = 111h + 31 ). For example, if ( h = 0 ), the number would be 31; if ( h = 1 ), it would be 142, and so on.
15
a + 2
The expression for 14 less than the quotient of 63 and a number ( h ) can be written as ( \frac{63}{h} - 14 ). Here, ( \frac{63}{h} ) represents the quotient of 63 and ( h ), and subtracting 14 gives the required expression.
The smallest prime number that is greater than 50 is 53.
The algebraic expression for 14 less than the quotient of 63 and the number H is ( \frac{63}{H} - 14 ). This expression first calculates the quotient of 63 and H, and then subtracts 14 from that result.
If twelve is more than half of H then H would have to be at the highest: 23 which does not equal 80.
Well, let's imagine a beautiful number "h" standing in a meadow. If we gently take away 8 from our lovely number "h," we are left with a smaller number that is just a little bit shy. It's like giving a small bird some space to fly freely in the sky.
A number h increased by i.e. added to itself = h + h =2h
The oxidation number for H is almost always 1+.
The oxidation number of hydrogen (H) in H2SO4 is +1.