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100

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What does 9 tens and 10 ones?

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thats a stupid thing

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Q: What does 9 tens and 10 ones?

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9 tens = 90. 4 fewer ones than tens = 9 - 4 = 5. Therefore the answer is 95.

(9*10)+(15*1) = 105

2 hundred = 2 × 100 = 200 5 ones = 5 × 1 = 5 9 tens = 9 × 10 = 90 3 tenths = 3 × 0.1 = 0.3 → 2 hundreds 5 ones 9 tens 3 tenths = 200 + 5 + 90 + 0.3 = 295.3

4 tens + 9 ones 3 tens + 19 ones 2 tens + 29 ones 1 ten + 39 ones 49 ones.

What is 9 tens 10 ones=

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9 tens + 12 ones = 9 × 10 + 12 × 1 = 90 + 12 = 102.

100 = (9x10) + (10x1) = 90 + 10

5 thousands = 5000. 10 tens = 100. 3 hundreds=300. 9 ones = 9. That's 5000 + 400 + 9, which is 5409

9 tens = 90. 4 fewer ones than tens = 9 - 4 = 5. Therefore the answer is 95.

What number has 9 tens and 4 fewer ones than tens

(9 × 10) + 9 = 99 is the number.

(9*10)+(15*1) = 105

The number is 16*10 plus 9*1 = 169

The general function is:1. y = a*x+bb is irrelevant and we can be removed2. y = a*xlets split x into ones and tens3. x = tens*10 + ones /e.g. 23 = 2*10 + 34. p1 = Multiplier of the onesp2 = Multiplier of the tens5. y = tens*10*p2 + ones*p1 /according to the question6. x*a = tens*10*p2 + ones*p1 /according to 2.7. (tens*10 + ones)*a = tens*10*p2 + ones*p1 /according to 3.8. tens*10*a + ones*a = tens*10*p2 + ones*p1 /regroup9. tens*10*a - tens*10*p2 + ones*a - ones*p1 = 0 /regroup10. tens*10*(a-p2) + ones*(a-p1) = 0 /regroup11. assuming "tens" and "ones" are not 0 then (a-p2) and (a-p1) must be 012. a-p2 = 0a-p1 = 013. a = p2a = p114. a = p1 = p2the answer is: when the Multipliers of ones and tens are equal then the product is called a.

(3*10)+(9*1)=39

There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }

2 hundred = 2 × 100 = 200 5 ones = 5 × 1 = 5 9 tens = 9 × 10 = 90 3 tenths = 3 × 0.1 = 0.3 → 2 hundreds 5 ones 9 tens 3 tenths = 200 + 5 + 90 + 0.3 = 295.3