To solve for b in the equation b + 15 = 27, you need to isolate b on one side of the equation. To do this, you can subtract 15 from both sides of the equation. This gives you b = 27 - 15, which simplifies to b = 12. Therefore, b equals 12 in the given equation.
The answer is 27. 10+15=25. 25+2=27.
3
In math problems without punctuation such as brackets, the standard convention in to solve from left to right. Therefore, you would solve the problem 15-3 times 4 plus nine like by three actions. 15-3 equals 12; 12 times 4 equals 48; 48 plus 9 equals 57.
'63'
55 + 34 + 31 + 27 + 21 + 21 + 20 + 17 + 15 + 15 = 256
3n = 15 + 12 = 27, 27/3 = 9 = n
15
139
The answer is 27. 10+15=25. 25+2=27.
4 + 15 = 19 + 8 + = 27 (alterative)
42
15
x = 27
3*-5+27 equals 12.
122 !
27-g = 2g+12 -3g = -15 g = 5
-17h + 27 = 20h so 27 = 20h + 17h = 37h Then h = 27/37 = 0.7297 approx.