Distance = speed x time s = vt v = s/t = 10 km/.75 hours = 13.33 km/hr
s=vt t=s/v ATQ 50=150/t so t=3 and 30=150/t t=5 avg speed=total distance / total time so 150+150/5+3 =300/8=37.5=avg speed
Minute Venitlation is easiest calculated by multiplying the tidal volume (Vt) X Rate
S=vt-16t2 solve for v is what I will assume you mean. first pull out the t S=t(v-16t) then devide by t S/t=v-16t Then add 16t to both sides S/t + 16t = v This can also be written as (S+16t2)/t = v
formula: h=-16t^2+vt+s H= final height T= time V= velocity S= starting height
velocity is nothing but speed of a body in the given direction. suppose if body is moving with constant velocity then VT graph will be parallel to the X -axis, if not then the VT graph is not parallel to the X-axis it means then object is moving with different velocity or it has its dierection or both velocity and aswell as direction.
Let s denote distance v denote speed t denote time. s = integral(v)dt If speed is constant, s = vt.
Rd= Vt*c/I Vt=KT/q, K=Boltzmann constant C= constant 2 for si 1 for Ge I current through the diode
This method assumes a constant speed, and can be used if there is an object travelling from Sun to Earth, or from Earth to Sun (at constant speed, of course), and you know both the speed and the time it takes. It doesn't seem to be a very practical method in this case. Note that if you throw an object toward the Sun, it will go faster and faster, due to the Sun's gravitation, so you wouldn't have a constant speed. You can use the equivalent formula with integrals, of course.
Just use the basic formula for constant speed: d = vt (distance = velocity x time). Solving for time: t = d/v.
Where the law is concerned - ANYTHING is possible. Realistically, they might simply place a warrant on file for you and if you appear again in VT, and come to the attention of the authorities, you will just be arrested then.
That depends on the speed. Choose a suitable speed, then use the formula: d = vt (distance = speed x time).
did vtu announce grace marks for the subject graph theory 4th sem(2006 scheme) exam was held on june 24th 2013
A car moving at a constant speed (no acceleration) will be defined as V= D/T where V= velocity, D= distance, and T= time. rearranging you could also see: D= VT or T=D/V.
As speed=Distance/time, distance would be, distance = Speed x time or, s = vt where s is distance, v is speed or change in velocity and t is time
It's a 5 Speed
There are about 20 miles between Bristol VT and Bridport VT.