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How can you prepare 250cm3 of 0.5m mgso4 from stock solution of 2.5m mgso4?
Just put both of them together use your common sense duh😂😂😂
What will be the final volume of a solution prepared by diluting 25 mL of 8.25 M sodium hydroxide to a concentration of 2.40?
The final volume of the solution will be 68.18 mL. This can be calculated using the formula for dilution, which is M1V1 = M2V2. Solving for V2 (final volume) gives V2 = (M1V1) / M2 = (8.25 M * 25 mL) / 2.40 M = 68.18 mL.
If 50 ml of 50 M Hydrogen Cloride is used to completely neutralize 25 ml of KOH solution what is the molarity of the base?
m1v1 = m2v2 50 mL * 50 M = 25 mL * X M X = 100
If 25.00ml of 50m naoh is used to titrate 26.25ml of hcl to the equivalence point what is the concentration of the hcl?
Using the equation M1V1 = M2V2, where M1 is the concentration of NaOH, V1 is the volume of NaOH used, M2 is the concentration of HCl, and V2 is the volume of HCl used, we can calculate the concentration of HCl to be 48.48 M.
A 40Kg football player leaps through the air to collide with and tackle a 60Kg player heading toward him also in the air. If the 40Kg player is heading to the right at 7M per S and the 60Kg player...?
The collision would involve momentum conservation, where the total momentum before the collision is equal to the total momentum after the collision. By using the equation (m1v1) + (m2v2) = (m1v1') + (m2v2'), you can solve for the final velocities. The direction and speed of the players after the collision would depend on the angle and intensity of the impact and the individual masses and velocities.
What is the molarity of a hydrochloric acid solution prepare by diluting 200.0mL of 0.500 M HCl to a total volume of 1.00 L?
The molarity of the final solution can be calculated using the formula: M1V1 = M2V2. By plugging in the values, we get (0.500 M)(0.200 L) = M2(1.00 L). Solving for M2 gives us 0.100 M for the final molarity of the solution.
How do you solve a dilution problem in Chem?
To solve a dilution problem in chemistry, you typically use the formula M1V1 = M2V2, where M1 is the initial molarity, V1 is the initial volume, M2 is the final molarity, and V2 is the final volume. Plug in the values you have and solve for the unknown. Make sure to keep track of units and use appropriate conversion factors if needed.
What volume of 8.0 M H2SO4 is required to prepare 200.0 ml of a 0.50 M?
To prepare a 0.50 M solution using 8.0 M H2SO4, you would need to dilute the concentrated solution with water. Using the formula M1V1 = M2V2, where M1 is the initial concentration, V1 is the initial volume, M2 is the final concentration (0.50 M), and V2 is the final volume (200.0 mL), you can calculate the volume of 8.0 M H2SO4 needed. This would be around 1.25 mL.
How many ltiers of 30 M HCl could be made with 3.0 L of 50 MHCl?
To do this use the formula Where M1 = concentration of what you have and M2 is the concentration you are trying to achieve. And V1 is the volume you have and V2 is the volume you want. So in this case we have 3.0L(50 M HCl) = X L(30 M HCl) and solve for X. (X = 5 L) M1V1 = M2V2
How many Ml of 14.5 M NH3 are needed to prepare 2.00 L of a 1.00 M solution?
To prepare a 1.00 M solution from a 14.5 M NH3 solution, you'll need to dilute it. By using the formula: M1V1 = M2V2, you can calculate the volume of 14.5 M NH3 needed. Plugging in the values, you get 138 mL of 14.5 M NH3 needed.
What does 4 equals M M stand for?
4 Minute Mile
What is the molarity of 25.0 mL of 3.50 M HNO3 diluted to 0.250L?
To find the new molarity after dilution, we can use the formula M1V1 = M2V2. Plugging in the values, (3.50 M)(0.025 L) = M2(0.250 L), we find that M2, the new molarity, is 0.35 M.
