To solve the equation 5.6 + k = 10, you need to isolate the variable "k" on one side of the equation. Start by subtracting 5.6 from both sides to get k = 10 - 5.6. This simplifies to k = 4.4. Therefore, the value of k that satisfies the equation is 4.4.
10-k=5
k=4
36.64
y = 3x + 2x^2 + k where k is any number
y = x/k so 15 = 6/k making k = 0.4. when x = 10 y = 10/0.4 ie 25 alternatively y/x = k ie 15/6 = k so k = 2.5; y/10 = 2.5 making y = 25.
-10
9.333 x 6 = 56
Yes, they are exactly the same, both of them increment k in 1.
k equals 5.6
k = 0.1
50
2
10-k=5
Equation: x^2 +2kx +10x +k^2 +5 = 0 Using the discriminant: (2k +10)^2 -4*1*(k^2 +5) = 0 Solving the discriminant: k = -2
It simplifies to 7k = 49 which gives k = 7.
If: y = 3x +1 then y^2 = 9x^ +6x +1 If: x^2 +y^2 = k then 10^x^2 +6x +(1-k) = 0 Using the discriminant: -4 +40k = 0 Add 4 to both sides: 40k = 4 Divide both sides by 40: k = 1/10 Therefore the value of k is 1/10
S equals -10t2 plus vt plus k This is one of the three formulae for motion. The standard form is S = ut + 1/2ft2. S = distance, u = initial velocity, f = acceleration, t = time, k is unknown. The equation in the question could thus be written, S = ut - 10t2 +k. This would imply that the acceleration is -10.