33*3=99
3*33=99
3 times 33 equals 99.
To find the answer to 987654321 that equals 99 using only addition, you can break down the number into its individual digits: 9 + 8 + 7 + 6 + 5 + 4 + 3 + 2 + 1 = 45. To reach 99, you would need to add 54 more. One way to do this is to add 50 and 4: 50 + 4 = 54. Therefore, the answer is 987654321 + 50 + 4 = 987654375.
99
198 divided by 2 equals 99. 99 times 2 equals 198.
102
If we interpret your question to mean finding an expression that equals 100 using three digits and including multiplication, division, subtraction, and addition, one possible solution is: ( (9 \times 11) + (3 - 3) = 99 + 1 = 100 ). Here, we use the digits 9, 1, and 0, and the operations requested. However, please clarify if you meant a different format or set of digits.
Applying the rules of BODMAS, whereby the actions of multiplication and division are carried out before the actions of addition and subtraction, 99 + (8 x 3) = 99 + 24 = 123.
First add all the addition together and add all the subtraction together. Then there will be the total addition and the total subtraction. Subtract the total subtraction from the total addition.99+98-97+96-95+94-93+92-91+90=(99+98+96+94+92+90)-(97+95+93+91)=569-376=193
99 divided into 9801 equals 99. This is because 9801 divided by 99 equals 99, as 99 multiplied by 99 equals 9801. Therefore, the answer is 99.
3*33 ■
2x-3 = 10x-99 start by moving the terms with variables (x) on one side of the equal sign, and the constants (regular number, with no variables) to the other side. Do this by addition and subtraction. 2x-3 = 10x-99 +99 +99 now you have 2x +96= 10x now get both of the variables on the right side 2x+96 = 10x -2x -2x now you have 96 = 8x now solve for x by dividing each side by 8 96/8 = 8x/8 x= 12
Number 99 is 100 - 1 = IC with 1 before 100 for subtraction
3 times 33 equals 99.
This equals 198.
-99
100-1 101-2 102-3
198/2 = 99