7
60
The number 100,002 is divisible by 3. The largest 5 digit number is 99996 (6 less).
1000 ÷ 8 = 125 → largest less than 1000 divisible by 8 is 124 x 8 = 992
Yes, a set of even numbers less than 8 would include the numbers 2, 4, and 6. Even numbers are integers that are divisible by 2, meaning they have a remainder of 0 when divided by 2. In this case, the even numbers less than 8 are 2, 4, and 6.
idhytugh
No.
There are no odd multiples of 6. If a number is a multiple of 6 then it is divisible by 6. If a number is divisible by 6 it is also divisible by 2 and 3 (see the fundamental theorem of arithmetic). If a number is divisible by 2 then it is even by definition. Therefore any number divisible by 6 is even.
60
Prime numbers, except 2, are always odd (they would not be prime if they were even cos they would be divisible by 2.) 1 less than any odd number must be an even number.
No. As 6 is less than 130 it cannot be a whole number multiple of 130 so 6 is not divisible by 130. If you meant is 130 divisible by 6, then: 130 is even and 6 is even, so possibly, but 1 + 3 + 0 = 4 which is not divisible by 3, so 130 is not divisible by 3 and so not divisible by 6.
No number meets these criteria. The number must be between 41 and 49. The only number in that range that is evenly divisible by 11 is 44, but 44 is even, not odd.
The number is 2424 > 2024 < 3024 / 3 = 824 / 2 = 12
The foolproof way is to divide 4 into it. If the answer is a whole number, it's divisible by 4. You can also tell by looking at it. If the last two digits are a multiple of 4, like 24 or 80, the whole number is divisible by 4.
No. To be divisible by a number it must be greater than, or equal to, that number. 10 is less than 66, so 10 cannot be divisible by 66.
18
To find a number less than 100 that is divisible by 2, 5, and 9, we need to find the least common multiple (LCM) of these three numbers. The LCM of 2, 5, and 9 is 90. Therefore, the number less than 100 that is divisible by 2, 5, and 9 is 90.
There is no smallest number since if any number is divisible by 8, then 8 less than that number is also divisible by 8 - and that argument continues all the way to minus infinity!The smallest positive number divisible by 8 is 8, itself.