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What forms when the ion product is greater than Ksp?

Anonymous

∙ 12y ago

Updated: 4/28/2022

If the ion product concentration is greater than the Ksp value a precipitate will form. If it equals the Ksp the solution is saturated and no precipitate forms.

Wiki User

∙ 12y ago

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Q: What forms when the ion product is greater than Ksp?

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When comparing Q to Ksp an initial Q value greater than Ksp indicates that?

It means a precipitate will form

When comparing q to ksp an inital q value greater the ksp indicates that what?

A precipitate will form

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Related Questions

How can one determine if a precipitate will form from a given Ksp value?

To determine if a precipitate will form from a given Ksp value, compare the ion product (Q) to the Ksp value. If Q is greater than Ksp, a precipitate will form. If Q is less than Ksp, no precipitate will form.

What is the relationship between Ksp and the product of ion concentrations in terms of determining whether a solution if those ions is saturated?

The relationship is that the product of the ion concentrations must equal the Ksp value for the solution to be saturated. If the product exceeds the Ksp value, then a precipitation reaction will occur until equilibrium is reached. Conversely, if the product is less than the Ksp value, the solution is not saturated and more solute can dissolve.

When comparing Q to Ksp an initial Q value greater than Ksp indicates that?

It means a precipitate will form

What can you say about a solution when Qsp is greater than Ksp?

If Qsp is greater than Ksp, it means the solution is supersaturated with respect to the solute. This may lead to precipitation of excess solute until equilibrium is re-established.

When comparing q to ksp an inital q value greater the ksp indicates that what?

A precipitate will form

What is the symbol for the solubility product constant?

The symbol for the solubility product constant is Ksp. It represents the equilibrium constant for the dissolution of a sparingly soluble compound in a solvent.

What is the relationship between the equilibrium constant (Ksp) and the reaction quotient (Q) in the context of the equilibrium constant expression (Kf) for a chemical reaction?

The equilibrium constant (Ksp) is the ratio of the concentrations of products to reactants at equilibrium, while the reaction quotient (Q) is the same ratio at any point during the reaction. When Q is less than Ksp, the reaction will shift to the right to reach equilibrium. When Q is greater than Ksp, the reaction will shift to the left.

What reflects the solubility product that contains ksp?

The solubility product constant, Ksp, reflects the maximum concentration of ions in a saturated solution of a sparingly soluble salt. It is the equilibrium constant for the dissolution of the solid salt into its constituent ions in solution. The larger the Ksp value, the more soluble the salt is in water.

What is the Solubility Product Constant Ksp for AgNO3?

The solubility product constant, Ksp, for AgNO3 (silver nitrate) is 5.6 x 10^-5. It represents the equilibrium constant for the dissolution of silver nitrate in water to form silver ions (Ag+) and nitrate ions (NO3-).

Does ksp change with concentration?

No, the solubility product constant (Ksp) does not change with concentration. It is a constant value that represents the equilibrium between an ionic solid and its ions in a saturated solution at a given temperature.

What is the difference between the equilibrium constant Kf and the solubility product constant Ksp in a chemical reaction?

The equilibrium constant Kf measures the extent of a reaction at equilibrium, while the solubility product constant Ksp measures the extent of a substance dissolving in a solution.

How do you calculate solubility of potassium nitrate?

The solubility of potassium nitrate can be calculated using its solubility product constant (Ksp). The Ksp value for potassium nitrate is determined experimentally and represents the product of the concentrations of the ions in a saturated solution of the compound. By using the Ksp value, you can set up an equilibrium expression and solve for the solubility of potassium nitrate in moles per liter.

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