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The half of iodine-125 is 60 days.What fraction of iodine-125 nuclides would be left after 360 days?
Assuming that "half" refers to "half-life", 360/60 = 6 so fraction left = 1/26 = 1/64
A rope is cut in half and half is discarded From the remaining half 1 quarter is cut off and discarded What fraction of the original rope is left?
3/8
How much Cu-61 (half-life about 3 hours) would remain from 2 mg sample after 6 hours?
6 hours = 2 half lives, thus 25 % would remain. 0.25 x 2 mg = 0.5 mg.Done another way...fraction remaining = 0.5^n where n = number of half lives = 6hr/3hr = 2fraction remaining = 0.5^2 = 0.250.25 x 2 mg = 0.5 mg
What fraction of U-238 atoms present at 1 half-life remain after 2 half-lives?
1/2 (50%) of them.
What fraction is closest to 0?
There is no possible answer. For any given fraction, half that fraction is another fraction and it will be closer to 0. And then half of that will be closer still, and then half of that ... . Hope you get the idea.
How much iodine has decay if 5 half lives have passed?
After 5 half-lives, 31.25% of the original iodine remains, meaning 68.75% has decayed. Each half-life reduces the amount of the original substance by half, so after 5 half-lives, the remaining fraction is ( \left(\frac{1}{2}\right)^5 = \frac{1}{32} ). Therefore, the decay percentage is calculated as ( 1 - \frac{1}{32} = \frac{31}{32} ), which is approximately 96.875%.
What fraction of a radioisotope is remaining if it undergoes six half-lives?
If a radioisotope undergoes six half-lives, only (1/64) or (0.015625) of the original radioisotope remains, because half of the remaining material decays at each half-life.
How long will it take for a 12.0-g sample of iodine-131 to decay to leave a total of 1.50 g of the isotope The half-life of iodine-131 is 8.07 days?
half life is 8.1 days, so it takes 8.1 days for half the iodine sample to decay. It takes another 8.1 days for half of the remaining sample (ie. 1/4th of the original sample) to decay. So it takes 16.2 days for 3/4th of the sample to decay.
What percentage of a radioactive sample remains after 5 half-lives?
After 5 half-lives, 3.125% (or 1/2^5) of a radioactive sample remains. Each half-life reduces the sample by half, so after 5 half-lives, there is only a small fraction of the original sample remaining.
After three half-lives what percent of the radioactive isotope is remaining?
After three half-lives, 12.5% of the radioactive isotope is remaining. This is because each half-life reduces the amount of radioactive material by half.
Why After three half-lives what fraction of a radioactive sample remains?
After three half-lives, only 1/8 (or 12.5%) of the original radioactive sample remains. This is because each half-life reduces the amount of radioactive material by half, so after three half-lives, you would have (1/2) * (1/2) * (1/2) = 1/8 of the original sample remaining.
The half of iodine-125 is 60 days.What fraction of iodine-125 nuclides would be left after 360 days?
Assuming that "half" refers to "half-life", 360/60 = 6 so fraction left = 1/26 = 1/64
How much hydrogen-3 will remain after 60 years if the original sample have a mass 80.0 g and a the half-life of hydrogen-3 is 12 years?
Fraction remaining = 0.5^n where n = # of half lives that have elapsed60 yrs x 1 half life/12 yrs = 5 half lives have elapsed Fraction remaining = 0.5^5 = 0.03125 mass remaining = 0.03125 x 80.0 g = 2.5 g remaining
What is the amount of the original carbon-14 remaining after two half lives?
After two half lives, 25% of the original carbon-14 would remain. This is because half of the remaining carbon-14 decays during each half life, leaving you with 50% after one half life and 25% after two half lives.
How much of an 80-milligram sample of Iodine-131 would be left after 32 days?
After 32 days, approximately 5 milligrams of the 80-milligram sample of Iodine-131 would be left. Iodine-131 has a half-life of about 8 days, so after each 8-day period, half of the remaining sample will decay.
After three half lives what fraction of the daughter product has formed?
91.16% of the daughter product has formed after 3.5 half lives.
What fraction of chlorine 36 remains undecayed after 2000000 years?
the half-life of chlorine 36 is 400,000 years. 200,000 years is 1/2 of a half life. in general, the formula to calculate the fraction of remaining amount is 1/2^n, where n represents the number of half-lives that have passed. in this case, n=1/2, or 0.5, therefore the remaining fraction is 1/2^0.5. Use your calculator and you will find that this is 0.707, or about 71% of the original amount. hope this helps
