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The shape is called the teardrop shape!

In 2-dimensions, its parametric equation is

x = sin(t)*sinm(t/2)

y = cos(t) for -pi < t < pi

The integer constant, m, changes the shape of the teardrop. At m = 0 the shape is a circle and as m increases the shape gets a pointier the top. I think 3 is about right.

The 3-d version is obtained by rotating this shape about the y axis.

The shape is called the teardrop shape!

In 2-dimensions, its parametric equation is

x = sin(t)*sinm(t/2)

y = cos(t) for -pi < t < pi

The integer constant, m, changes the shape of the teardrop. At m = 0 the shape is a circle and as m increases the shape gets a pointier the top. I think 3 is about right.

The 3-d version is obtained by rotating this shape about the y axis.

The shape is called the teardrop shape!

In 2-dimensions, its parametric equation is

x = sin(t)*sinm(t/2)

y = cos(t) for -pi < t < pi

The integer constant, m, changes the shape of the teardrop. At m = 0 the shape is a circle and as m increases the shape gets a pointier the top. I think 3 is about right.

The 3-d version is obtained by rotating this shape about the y axis.

The shape is called the teardrop shape!

In 2-dimensions, its parametric equation is

x = sin(t)*sinm(t/2)

y = cos(t) for -pi < t < pi

The integer constant, m, changes the shape of the teardrop. At m = 0 the shape is a circle and as m increases the shape gets a pointier the top. I think 3 is about right.

The 3-d version is obtained by rotating this shape about the y axis.

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11y ago

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The shape is called the teardrop shape!

In 2-dimensions, its parametric equation is

x = sin(t)*sinm(t/2)

y = cos(t) for -pi < t < pi

The integer constant, m, changes the shape of the teardrop. At m = 0 the shape is a circle and as m increases the shape gets a pointier the top. I think 3 is about right.

The 3-d version is obtained by rotating this shape about the y axis.

User Avatar

Wiki User

11y ago
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Q: What geometric shape is a teardrop?
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