Well, isn't that just a happy little math question! If we're trying to find what numbers can divide evenly into both 112 and 200, we can start by finding the factors of each number. For 112, the factors are 1, 2, 4, 7, 8, 14, 16, 28, 56, and 112. For 200, the factors are 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, and 200. So, the numbers that go into both 112 and 200 are 1, 2, 4, 8. Happy little numbers, just hanging out together!
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To find what numbers evenly divide into both 112 and 200, we need to find the greatest common factor (GCF) of the two numbers. First, we find the prime factorization of each number: 112 = 2^4 * 7 and 200 = 2^3 * 5^2. The GCF is the product of the common prime factors raised to the lowest power they appear in both numbers, which is 2^3 = 8. Therefore, 8 is the greatest number that goes into both 112 and 200.
The factors of 112 are 1, 2, 4, 7, 8, 14, 16, 28, 56, 112;
the factors of 200 are 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 200;
the common factors of 112 and 200 are 1, 2, 4, 8.
Exactly 112 times
To find out how many times 21 goes into 112, you would perform division. Divide 112 by 21 to get the quotient. In this case, 112 ÷ 21 equals 5 with a remainder of 7. Therefore, 21 goes into 112 five times with a remainder of 7.
112 ÷ 12 = 9 with remainder 4 or 9.33
To find out how many times 75 goes into 112, you would perform long division. When you divide 112 by 75, you get a quotient of 1 with a remainder of 37. This means that 75 goes into 112 one time with a remainder of 37.
112/14=8R0 So 8 times.