If you mean: ax2+bx+c = 0 which is the general form of a quadratic equation whereas a is > 0 and any increases to the value of a will effect the solutions of the equation.
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Ax2+By2+Bx+Cy+D=0
Two: one is 0, the other is -b/a ax2 + bx + c = 0, but c = 0 ⇒ ax2 + bx + 0 = 0 ⇒ ax2 + bx = 0 ⇒ x(ax + b) = 0 ⇒ x = 0 or (ax + b) = 0 ⇒ x = -b/a
x = [−b ± √(b2 − 4ac)]/2aA, B, and C can all correspond to the original quadratic equation as follows: ax2 + bx + c = 0The quadratic formula can only be used if the quadratic equation is equal to zero.If [ Ax2 + Bx + C = 0 ], thenx = [ -B +/- sqrt( B2 - 4AC ) ]/ 2A
Write the quadratic equation in the form ax2 + bx + c = 0 then the roots (solutions) of the equation are: [-b ± √(b2 - 4*a*c)]/(2*a)
If quadratic equation is ax2+bx+c then by shree Dharacharya formula roots of equation can be found by this formula (-b+-sqrt(b2-4ac))/2a