Q: What is -2 parenthesis x plus 4 parenthesis?

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x squared plus 9x plus 20.

5X + 2X + 7 when X=2 Replace X with 2 (5x2) + (2x2) +7 Work parenthesis first 7 + 4 + 7 Answer 7 + 4 + 7 = 18

y + 12 = -3(x - 2) y + 12 = -3x + 6 y = -3x - 6 or y = -3(x + 2)

y=3x(x+7)^2

x^2/x +2=4/x +2 (x^2/x)-(4/x)=0 (x^2-4)/x=0 x^2-4=0 (x+2)(x-2)=0 x=±2

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x squared plus 9x plus 20.

What I mean by this equation is: x^3-2x^(x-2.5)+x^(x^x)

You are given: G(x) = x2 + x So if you want to solve G(2), all you need to do is replace all occurrences of "x" with the number 2, then work out what it comes to. G(2) = 22 + 2 ∴G(2) = 4 + 2 ∴G(2) = 6

5X + 2X + 7 when X=2 Replace X with 2 (5x2) + (2x2) +7 Work parenthesis first 7 + 4 + 7 Answer 7 + 4 + 7 = 18

12x = 4(x+5) 3x = x+5 divide by 4 2x = 5 subtract x x = 2.5 divide by 2

a=64 b=8 (x+16x+64)=(x+8)^2

5 + 2 x 4 + 1 =PEMDAS (parenthesis, exponents, multiplication, division, addition, subtraction)5 + 8 + 1 = 14

(x2y2)3 + (x3y3)2 = 2x6y6.

(7 + 2) x 6 - 4 - 3 = 9 x 6 - 4 - 3 = 54 - 4 - 3 = 54 - 1 = 53

(16 x 22)2 = (16 x 4)2 = (64)2 = 4096. Always perform the operations inside parenthesis first.

y + 12 = -3(x - 2) y + 12 = -3x + 6 y = -3x - 6 or y = -3(x + 2)

(x+8)(x-1)=0 x+8=0 x=-8 x-1=0 x=1 Therefore, the zeroes are -8 and 1.