x=2 y=7 5x+3y= 5 7 x 2 x 3 ____ _____ 10 21 21 + 10 _______ 31
7-1=6
7 + 8y - 3y + 2 =7 + 2 + 8y - 3y = 9 + 8y - 3y = 9 + 5y
Divide all terms by -3 then it will be in slope intercept form
8x-7 plus 2x equals 6 plus 5x plus 2?
5y+14+y = 3y-7 5y+y-3y = -7-14 3y = -21 y = -7
x-y = 6 -x-3y = 22 -4y = 28 y = -7 So by substituting: x = -1 and y = -7
The ordered pair is (-1, -7).
4y + 7 = 3y + 9-3y-7 -3y-7y = 24(2) + 7 = 3(2) + 98 + 7 = 6 + 915 = 15
given is that 4x+3y=6(3x+3y)=7 i.e., 6(3x+3y)=7 &&& 4x+3y=7 ---------------(1) 3x+3y=7/6 x+y=7/18 _________(2) multiply eqn(2) by 4 4x+4y=28/18 -------------------------(3) (3)-(1) 4x+3y-4x-4y=7-(28/18) y= -98/18 substitute y in eqn(2) x-98/18=7/18 x=7/18+98/18 x=105/18. therefore x=105/18 : y= -98/18
(5, 1)
are you talking about a system of equations where x+3y=-7 -x+2y=-8 if so, then the answer is {2,-3}
{-4,-5}
x + 8y = 3 therefore 2x + 16y = 6 (a) 2x + 3y = -7 (b) Subtract (b) from (a): 13y = 13 so y = 1 and x = -5
7
4y + 7 - y = 10 + 3y My next step is to combine the y's on the left, 3y + 7 = 10 + 3y If I then subtract 3y from both sides I obtain 7 = 10 which is not a true statement. Hence, the equation that you presented is invalid.
X equals 1 and so does Y