Written in base two its a 1 followed by 1000 zeroes. I doubt anyone will count the zeroes to check. Writing it in base 10 is a colossal waste of time, no one wants to read it, but as I recall there's a repeating pattern to the digits of the powers of a number, and that would be a preferable way to complete the exercise rather than computing the number. That should be enough of a hint to anyone serious about tackling the question. The answer is to state the digit pattern and the number of digits, which you get from log10(2^1000) which is 1000*log10(2)
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0002 is the same as 2 and 0009 is the same as 9 So 2 is less than 9
1000*105 = 100000000.
10 to the power of 3. 103
1,000,000,000,000
well .0001 is 1 millionths, .0002 is 2 millionths and so on