The three numbers on a bag of fertilizer indicate the percentage of nitrogen, phosphorus, and potassium available. So in the case of 0,0,60 fertilizer, there is 60% potassium available with no nitrogen & phosphorus.
-60
300=240*1+60 240=60*4+0 HCF = 60 360=60*6+0 HCF =60
60+60=120 just add 0+0=0 then,6+6=12 so,120
what's between 120 and 60 degrees east in longitude? There's a number line that is latitude has 90 N 60 30 0 30 60 S. and the longitude 60 120 180 120 60 0 60 E
-77
0-0-60 fertilizer is straight Potassium or commonly referred to as "potash"
0% of 60 = 0 * 60 = 0
It usually refers to the ratio of nitrogen (N), phosphorous (P) and potassium (K) in the fertilizer. So 10-0-0 means that there is no phosphorous or potassium, only 10 parts nitrogen per 100 parts fertilizer.
0 - 60 = -60
The 0-11-52 means 0% Nitrogen (N), 11% Phosphorous (P) and 52 Potassium (K). The ratio of P to K that you need is 35/60 or ~ 1/2, but the P to K ratio of your "fertilizer" is 11/52 or ~ 1/5. You should get a fertilizer with a ratio more in line with what you need or expect to have to apply multiple fertilizers. Here is how you work out how much to apply per acre for each nutrient. Using Potassium as an example lbs to apply per acre = <lbs nutrient required per acre> / <% nutrient> lbs K to apply per acre = 60 / 0.52 ~ 120 lbs But like I said you would not get the correct amount of P with this fertilizer.
34-0-0
0. 60/0=0,so mathematically there are no zeros in the quantity of 60.
16% Nitrogen 20% Phosphorous 0% Potash.
A nitrogen fertilizer is what is used to fertilize pecan trees (Carya illinoiensis).Specifically, ammonium nitrate is an effective, reasonably priced nitrogen fertilizer for pecan trees. It is sold in packages marked 33-0-0 for 33% weight of nitrogen and 0% each of phosphorus and potassium. Another effective, reasonably priced nitrogen fertilizer is ammonium sulfate (21-0-0), at 21% nitrogen.
nitrogen phosphorus potassium
0-60 in 4.2 seconds
If you mean: y = -15x+60 then 15x+y = 60 When y = 0 then x = 4 When x = 0 then y = 60 Coordinates of the line are: (4, 0) and (0, 60)