0
1 1 0 (one zero) is zero. If your thumb got in the way and there's not supposed to be a space, then 10 is 2 in decimal if the 10 is binary. If it's hexadecimal, it's still 2 in decimal. Or maybe it's the title of the 1979 movie with Bo Derek.
See what ambiguity gets you?
Wiki User
∙ 15y ago
Wiki User
∙ 13y agoIt appears to be binary.
Converted ASCII: h( i
Converted to hex: D05040D2
Converted to decimal: 3494920402
Add your answer:
Earn +20 pts
Calculate the first 10 numbers in base 2?
0 . . . . . 0 0 0 0 1 . . . . . 0 0 0 1 2 . . . . . 0 0 1 0 3 . . . . . 0 0 1 1 4 . . . . . 0 1 0 0 5 . . . . . 0 1 0 1 6 . . . . . 0 1 1 0 7 . . . . . 0 1 1 1 8 . . . . . 1 0 0 0 9 . . . . . 1 0 0 1 10 . . . . 1 0 1 0
How dual of xor is equal to its complement?
| x | y | x' | y' | x⊕y | x'⊕y' | ---------------------------------- | 0 | 0 | 1 | 1 | 0 | 0 | | 0 | 1 | 1 | 0 | 1 | 1 | | 1 | 0 | 0 | 1 | 1 | 1 | | 1 | 1 | 0 | 0 | 0 | 0 |
What is the binary code for 1?
Here they are for 1 to 16, at no extra cost:Dec . . . Bin1 . . . . . 12 . . . . . 1 03 . . . . . 1 14 . . . . . 1 0 05 . . . . . 1 0 16 . . . . . 1 1 07 . . . . . 1 1 18 . . . . . 1 0 0 09 . . . . . 1 0 0 110 . . . . 1 0 1 011 . . . . 1 0 1 112 . . . . 1 1 0 013 . . . . 1 1 0 114 . . . . 1 1 1 015 . . . . 1 1 1 116 . . . . 1 0 0 0 0
Given 5 zeros using any mathematical operations can you make a total of 120?
AnswerAnswer: ( 0! + 0! + 0! + 0! + 0! ) ! = 120 Explanation: Here we have used operator called " factorial ". As you know that 0! = 1 so, = ( 0! + 0! + 0! + 0! + 0! ) ! = ( 1 + 1 + 1 + 1 + 1 ) ! = (5 )! = 120 : ( 0! + 0! + 0! + 0! + 0! ) ! = 120 Explanation: Here we have used operator called " factorial ". As you know that 0! = 1 so, = ( 0! + 0! + 0! + 0! + 0! ) ! = ( 1 + 1 + 1 + 1 + 1 ) ! = (5 )! = 120
What is 0 minus negative 1?
0-(-1) is the same as 0+1, so 0-(-1)=1
Give truth table for excess-3 to bcd code converter?
Excess-3 BCD a B c d w x y z 0 0 1 1 0 0 0 0 0 1 0 0 0 0 0 1 0 1 0 1 0 0 1 0 0 1 1 0 0 0 1 1 0 1 1 1 0 1 0 0 1 0 0 0 0 1 0 1 1 0 0 1 0 1 1 0 1 0 1 0 0 1 1 1 1 0 1 0 1 0 0 0 1 0 0 0 1 0 0 1 i'm not sure. but it should be the ans
What is the truth table for A B CY?
a b c y 0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 0 1 0 1 0 1 1 0 0 1 1 1 1 0 0 0 1 0 0 1 1 0 1 0 1 0 1 1 1 1 0 0 1 1 0 1 1 1 1 0 1 1 1 1 FORMULA FOR possibilities = 2 ^(no of variables). Here its 4 so, 2n=24=16 Hence we have 16 possibilities.
Design a truth table up to 4 variable?
w x y z 0 0 0 0 0 0 0 1 0 0 1 0 0 0 1 1 0 1 0 0 0 1 0 1 0 1 1 0 0 1 1 1 1 0 0 0 1 0 0 1 1 0 1 0 1 0 1 1 1 1 0 0 1 1 0 1 1 1 1 0 1 1 1 1 FORMULA FOR possibilities = 2 ^(no of variables). Here its 4 so, 2n=24=16 Hence we have 16 possibilities.
How do you express 1 2 3 etc in a digital format 0s and1s?
0 . . . 0 0 0 0 1 . . . 0 0 0 1 2 . . . 0 0 1 0 3 . . . 0 0 1 1 4 . . . 0 1 0 0 5 . . . 0 1 0 1 6 . . . 0 1 1 0 7 . . . 0 1 1 1 8 . . . 1 0 0 0 9 . . . 1 0 0 1 10 . . 1 0 1 0 11 . . 1 0 1 1 12 . . 1 1 0 0 13 . . 1 1 0 1 14 . . 1 1 1 0 15 . . 1 1 1 1 16. 1 0 0 0 0 . . etc.
What are the binary number for 1-10?
11
Calculate the first 10 numbers in base 2?
0 . . . . . 0 0 0 0 1 . . . . . 0 0 0 1 2 . . . . . 0 0 1 0 3 . . . . . 0 0 1 1 4 . . . . . 0 1 0 0 5 . . . . . 0 1 0 1 6 . . . . . 0 1 1 0 7 . . . . . 0 1 1 1 8 . . . . . 1 0 0 0 9 . . . . . 1 0 0 1 10 . . . . 1 0 1 0
How do you count in binary from twenty to twenty-five?
1 0 1 0 0 1 0 1 0 1 1 0 1 1 0 1 0 1 1 1 1 1 0 0 0 1 1 0 0 1
What are logic gates with truth table and or not?
AND A B Q 0 0 0 0 1 0 1 0 0 1 1 1 OR A B Q 0 0 0 0 1 1 1 0 1 1 1 1 NOT A Q 0 1 1 0 (I might as well carry on) XOR A B Q 0 0 0 0 1 1 1 0 1 1 1 0 NAND A B Q 0 0 1 0 1 1 1 0 1 1 1 0 NOR A B Q 0 0 1 0 1 0 1 0 0 1 1 1 BUF (NNOT) A Q 0 0 1 1 XNOR A B Q 0 0 1 0 1 0 1 0 0 1 1 1
Truth table of 1 to 16 demultiplexer?
Strobe A B C D Output (Y) 0 0 0 0 0 D0 0 0 0 0 1 D1 0 0 0 1 0 D2 0 0 0 1 1 D3 0 0 1 0 0 D4 0 0 1 0 1 D5 0 0 1 1 0 D6 0 0 1 1 1 D7 0 1 0 0 0 D8 0 1 0 0 1 D9 0 1 0 1 0 D10 0 1 0 1 1 D11 0 1 1 0 0 D12 0 1 1 0 1 D13 0 1 1 1 0 D14 0 1 1 1 1 D15 1 X X X X 1 where A,B,C,D are the control input or control nibble and the Boolean expression for Y is given as:- Y = A'B'C'D'D0 + A'B'C'DD1 + A'B'CD' D2 + A'B'CDD3 + A'BC'D'D4 + A'BC'DD5+ A'BCD'D6 + A'BCDD7 + AB'C'D'D8 + AB'C'DD9 + AB'CD'D10 + AB'CDD11 + ABC'D'D12 + ABC'DD13 + ABCD'D14 + ABCDD15
What is 1-0-0-1?
1 - 0 - 0 - 1 = 0
How dual of xor is equal to its complement?
| x | y | x' | y' | x⊕y | x'⊕y' | ---------------------------------- | 0 | 0 | 1 | 1 | 0 | 0 | | 0 | 1 | 1 | 0 | 1 | 1 | | 1 | 0 | 0 | 1 | 1 | 1 | | 1 | 1 | 0 | 0 | 0 | 0 |
How do you play the harmonica part of 'That's What Friends Are For' on a guitar?
E|----------------|-------0-1-0----|----------------|--------1-0-----|--| B|--0-1-----0-1--|--0-1--------1-|------0-1-------|------1----1---|--| G|0-------0------|0--------------2|0-------------0-|-----2-------2-|0-| D|----------------|-----------------|----------------|3--3------------|--| A|----------------|-----------------|----------------|-----------------|--| E|----------------|-----------------|----------------|-----------------|--| E|----3-1---------|-----------------0-|1---------------| B|--------1-------|-----------3-1-----|----------------| G|----------0-----|0-------0----------|----------------| D|------------2-3|----2-3------------|----------------| A|----------------|--------------------|----------------| E|----------------|--------------------|----------------| E|----------------|--------0-1-0----|----------------|-------1-0-----|--| B|--0-1-----0-1-|---0-1-------1--|------0-1-------|------1----1---|--| G|0-------0------|-0--------------2|0------------0-|-----2-------2-|0-| D|----------------|------------------|----------------|3--3-----------|--| A|----------------|------------------|----------------|----------------|--| E|----------------|------------------|----------------|----------------|--|
