60 degrees.
Oh, that's a happy little question! To convert gray code to binary, you can start by writing down the first bit as it is. Then, for each subsequent bit, you can add the gray code bit to the binary bit before it. So, for 10101111, the binary equivalent would be 11101010. Just remember, there are no mistakes, only happy little accidents!
A pair of complimentary angles has a sum that measures 90 degrees. If your first angle is 40 degrees, the complement must equal 50. 90= 40+X 50=X
+, -, *, /, and, or, xor
objective complement
| x | y | x' | y' | x⊕y | x'⊕y' | ---------------------------------- | 0 | 0 | 1 | 1 | 0 | 0 | | 0 | 1 | 1 | 0 | 1 | 1 | | 1 | 0 | 0 | 1 | 1 | 1 | | 1 | 1 | 0 | 0 | 0 | 0 |
It depends. XNOR is the inverse of XOR. If the N(ot) part is on the inputs, then they are equivalent. If the N(ot) part is on the output, then they are not.
45o
XORing X with 1 gives X', i.e., NOT(X). If we are able to construct a NAND (AND) using XOR, we can also obtain AND (NAND) from it, which makes XOR a universal gate since inverted inputs to a NAND (AND) will give OR (NOR). However XOR is not a universal gate! Therefore we cannot obtain NAND (AND) using XOR. :-) By, Tirtha Sarathi Ghosh Class 10 IIT Kanpur Aspirant
Yes. I'm assuming this is talking asking about boolean logic (the question makes little sense otherwise). If a and b are equal, then the complement of a and the complement of b are equal.
xor
1
Half of 90...
The bitwise XOR operator is ^, or shift 6. The bitwise XOR assignment operator is ^=.
a XOR b is a^b in C language
If the one's complement of the code is equal to the nine's complement of the code, then it is called a self complementing code.
60 degrees.