| x | y | x' | y' | x⊕y | x'⊕y' |
----------------------------------
| 0 | 0 | 1 | 1 | 0 | 0 |
| 0 | 1 | 1 | 0 | 1 | 1 |
| 1 | 0 | 0 | 1 | 1 | 1 |
| 1 | 1 | 0 | 0 | 0 | 0 |
60 degrees.
Oh, that's a happy little question! To convert gray code to binary, you can start by writing down the first bit as it is. Then, for each subsequent bit, you can add the gray code bit to the binary bit before it. So, for 10101111, the binary equivalent would be 11101010. Just remember, there are no mistakes, only happy little accidents!
A pair of complimentary angles has a sum that measures 90 degrees. If your first angle is 40 degrees, the complement must equal 50. 90= 40+X 50=X
+, -, *, /, and, or, xor
objective complement
| x | y | x' | y' | x⊕y | x'⊕y' | ---------------------------------- | 0 | 0 | 1 | 1 | 0 | 0 | | 0 | 1 | 1 | 0 | 1 | 1 | | 1 | 0 | 0 | 1 | 1 | 1 | | 1 | 1 | 0 | 0 | 0 | 0 |
It depends. XNOR is the inverse of XOR. If the N(ot) part is on the inputs, then they are equivalent. If the N(ot) part is on the output, then they are not.
To complement the 6th bit of the BX register in assembly language, you can use the XOR instruction. First, create a mask that has the 6th bit set (binary 00100000, which is 0x20 in hexadecimal). Then, XOR the BX register with this mask to toggle the 6th bit. Here's an example in x86 assembly: mov ax, <value> ; Load AX with some value xor bx, 0x20 ; Complement the 6th bit of BX This will flip the 6th bit of BX without affecting the other bits.
XORing X with 1 gives X', i.e., NOT(X). If we are able to construct a NAND (AND) using XOR, we can also obtain AND (NAND) from it, which makes XOR a universal gate since inverted inputs to a NAND (AND) will give OR (NOR). However XOR is not a universal gate! Therefore we cannot obtain NAND (AND) using XOR. :-) By, Tirtha Sarathi Ghosh Class 10 IIT Kanpur Aspirant
To complement the 6th bit of the BX register in assembly language, you can use the XOR instruction. The 6th bit corresponds to the bit mask 0x20 (binary 0010 0000). The code would look like this: MOV AX, 6 ; Load AX with 6 (not directly relevant to complementing BX) XOR BX, 0x20 ; Complement the 6th bit of BX This will toggle the 6th bit of BX, effectively complementing it.
45o
Yes. I'm assuming this is talking asking about boolean logic (the question makes little sense otherwise). If a and b are equal, then the complement of a and the complement of b are equal.
xor
The bitwise XOR operator is ^, or shift 6. The bitwise XOR assignment operator is ^=.
1
Half of 90...
a XOR b is a^b in C language