1.67 × 1024g written in regular notation is 1,670,000,000,000,000,000,000,000g
167 + 10 = 177
Well, there is... 1 x 167 2 x 83.5 4 x 41.75 8 x 20.875 16 x 10.4375
-167
43
4.08 x 10 to the 12th power is 4.08 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 which is 40.8 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 which is 408 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 which is 4080000000000
atomic mass unit
If the question is, What is the missing number in the sequence 7, 11, 23, ?, 167? Then each number is 3 times the previous number then deduct 10. 3 x 7 = 21 - 10 = 11 3 x 11= 33 - 10 = 23 3 x 23 = 69 - 10 = 59......the missing number 3 x 59 = 177 - 10 = 167 3 x 167 = 501 - 10 = 491....the next number in the sequence.
10% of 167 = 167*10/100 = 16.7
The Roman Numeral for 167 means 167. In Roman Numerals, 167 is written: CLXVII C= 100 L= 50 X= 10 V= 5 I= 1
2 x 2 x 2 x 167 (23 x 167).
The equation is: -167-10 = -177
167 + 10 = 177
You multiply 167 by .10 which is equivalent to 10%.
501 = 1 x 501, 3 x 167, 167 x 3, 501 x 1.
167 x 3.78 = 631.26
E.coli genome constist of a SINGLE circular chromosome containing 4.6 Mb i.e. 4.6 X 10^6 bases. The weight of one base is 330 daltons and 1 Dalton is equal to 1.661^-24g. there fore the CHROMOSOMAL WEIGHT (in micrograms) is 660 X 1.661 X 10^-18 X 4.6 X 10^6 which is equal to 5.043 X 10^-9 MICROGRAMS.
Well, there is... 1 x 167 2 x 83.5 4 x 41.75 8 x 20.875 16 x 10.4375