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There is an equation to find the sum of a list of numbers . It is called the Arithmetic Progression.

The equation is

S(n) = (n/2)[a + (n-1)d] 4

Where

n = number of terms (1000)

a = first term (1000)

d = difference between terms (1)

Hence

S(1000) = (1000/2)[1000 + ( 1000 - 1)(1)]

S(1000) = 500[ 1000 + 999]

S(1000) = 500[1999]

S(1000) = 999500 The answer!!!!!

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lenpollock

Lvl 16
12mo ago

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More answers

The answer is 500,500. (I did it on my calculator. It took forever. YOUR WELCOME!)

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Wiki User

15y ago
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