To subtract in base 2, we need to borrow from the next higher place value if necessary. In this case, when subtracting 11 from 101 in base 2, we need to borrow from the leftmost digit. So, 101 in base 2 is 5 in decimal, and 11 in base 2 is 3 in decimal. When subtracting 3 from 5 in decimal, we get 2 in decimal, which is 10 in base 2. Therefore, 101 base 2 minus 11 base 2 is 10 base 2.
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Oh, dude, you're hitting me with the binary math! So, 101 in base 2 is 5 in base 10, and 11 in base 2 is 3 in base 10. Subtracting 3 from 5 gives you 2 in base 10, which is 10 in base 2. So, the answer is 10 in base 2. Cool, right?
Well, darling, in base 2, 101 minus 11 is 10. It's as simple as that. Just subtract those binary numbers like you're taking candy from a baby.
101 in base 2 is 5 in decimal. 11 in base 2 is 3 in decimal. 5 - 3 is 2 in decimal. 2 is 10 in base 2.
a negative minus a positive is a negative ex: -12-13=-25 -9-2=-11 -100-1=-101
To subtract 11 in base 2 from 100 in base 2, you first convert both numbers to decimal. 100 in base 2 is equal to 4 in decimal (12^2 + 02^1 + 02^0). Similarly, 11 in base 2 is equal to 3 in decimal (12^1 + 12^0). Subtracting 3 from 4 in decimal gives you 1 in decimal, which is equal to 1 in binary (12^0). Therefore, 100 in base 2 minus 11 in base 2 equals 1 in base 2.
101/119 2/11:= [(11*9)+2]/11= [99+2]/11= 101/11 in improper fraction
(-2) - 11 = -13
13 - 2 = 11