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What is 785 divied by n eaquals 112 r 1?
To solve this, divide 112 into 784. n = 7
Who were the 12 dicsiples?
R a c h e l B r e e nH a n n a h B o l l a r dA s h t o n L o o n eN o r i k a C h y n o w e t hC a i t l i n S c o t tN a t a l i e W i l l i a m sM e g S o u t h a mS t e p h a n i e N e w i n g t o nE m m a H o a r eE m m i l i n e B r a d l e yJ e s s i c a F l o o dC a t h e r i n e H a n d l e y=)
How do you write thirteen and four tenths in expanded form?
T h i r t e e n a n d f o u r t e n t h s
What is 20 percent of 112?
20% of 112= 20% * 112= 0.2 * 112= 22.4
Can a sequence of numbers be both geometric and arithmetic?
Yes, it can both arithmetic and geometric.The formula for an arithmetic sequence is: a(n)=a(1)+d(n-1)The formula for a geometric sequence is: a(n)=a(1)*r^(n-1)Now, when d is zero and r is one, a sequence is both geometric and arithmetic. This is because it becomes a(n)=a(1)1 =a(1). Note that a(n) is often written anIt can easily observed that this makes the sequence a constant.Example:a(1)=a(2)=(i) for i= 3,4,5...if a(1)=3 then for a geometric sequence a(n)=3+0(n-1)=3,3,3,3,3,3,3and the geometric sequence a(n)=3r0 =3 also so the sequence is 3,3,3,3...In fact, we could do this for any constant sequence such as 1,1,1,1,1,1,1...or e,e,e,e,e,e,e,e...In general, let k be a constant, the sequence an =a1 (r)1 (n-1)(0) with a1 =kis the constant sequence k, k, k,... and is both geometric and arithmetic.
