the answer is 132 yeah
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Oh, dude, you're hitting me with the big math questions now? Alright, alright, let me put down my snacks for a sec and tell you that 11 times 12 equals 132. Like, it's not rocket science, but hey, now you know!
11 multiplied by 12 equals 132. This can be calculated by adding 11 twelve times, or by recognizing that multiplying by 11 is the same as multiplying by 10 and then adding the original number. In this case, 11 multiplied by 10 is 110, and adding another 11 gives the final result of 132.
22
11x12
66x2. 33x4 11x12
15 for example, but also any other number multiplied by 11 to which 4 is added. eg 11x12+4 = 136.
The first common multiple will be the least common multiple or LCM.Since 11 and 12 have no common factors, the LCM is 11x12 or 132.The numbers 11 and 12 are called relatively prime.
1B7 twelve x 29 twelve = 1B7 twelve x 9 twelve plus 1B7 twelve x 20 twelve First 1B7 twelve x 9 twelve is sum of 100 twelve x 9 twelve + B0 twelve x 9 twelve + 7 twelve x 9 twelve in base 10 7 x 9 = 63 = and that equals 53 twelve Next B0 twelve x 9 twelve is 11x12 in base 10 + 0 base 10 and that's 132 since 132 x 9 = 1188 in base ten. . 1188 = 8 x 144 + 3 x 12 + 0 x 1 so 1188 = 830 twelve Now 100 twelve times 9 twelve = 900 twelve so we have to add 53 twelve + 830 twelve + 900 twelve the ones column adds to 3, then twelves column is 5+3 =8 and the hundredfortyfours column is 8+9 = 17 base 10 which is 15 twelve so B0 twelve times 9 twelve equals 1583 twelve Now we have to determine 1B7 twelve x 20 twelve 1B7 twelve times 2 twelve is 200 twelve plus (22 base 10) x 10 twelve + 14 base 10 and that is 200 twelve + 1A0 twelve + 12 twelve = 3B2 twelve. we need to put a zero after that so it is 3B20 The final product is equal to 1583 twelve + 3B20 twelve and that is 4 [16]A3 twelve. we must get rid of that base 10 sixteen. Sixteen is 14 twelve so we put the 4 and carry the 1 and result is 54A3 twelve