0
132
(11x12)
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∙ 13y ago
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The first multiple of 11 without a repeated digit?
Do you mean 121 or 132?
How many 2 digit numbers can be formed with 0 through 5 where 0 is the first digit and others can not be repeated?
-- If 'zero' is always the first digit, then we're pretty darn sure that no other digit can be repeated in the same 2-digit number, since there's only one digit left to be filled in. -- If 'zero' is always the first digit, then there are exactly six possible 2-digit numbers: 00 01 02 03 04 and 05.
What is the least 6-digit number which is divisible by 6 with no repeated digits?
0
What is the first 3 digit multiple of 11?
110
What is the first 3 digit multiple of 9?
108
The smallest 12- digit number where repeated digits are allowed?
The first digit would have to be 1, the remaining digits, zero.
Is the second number of 271 a multiple of the first?
If you mean digit, the answer is NO.
How many 5 digit numbers are there with distinct numbers?
I suspect you mean "without repeated digits", and I'll answer it that way.Here's how I would construct all the 5-digit numbers without repeated digits:The first digit can be any one of 9 (1 thru 9 but not zero). For each of these . . .The second digit can be any one of 9 (zero thru 9 but not the same as the first one). For each of these . . .The third digit can be any one of the remaining 8. For each of these . . .The fourth digit can be any one of the remaining 7. For each of these . . .The fifth digit can be any one of the remaining 6.Total number of possibilities = (9 x 9 x 8 x 7 x 6) = 27,216
What is the sum of the product of the first 5 digit number and 5 digit multiple of 6?
The question is a bit ambiguous: "the sum of the product ... " does not seem to make sense. The first 5 digit number is 10000 the first 5 digit multiple of 6 is 10002 Their product is 100020000. I am not sure what to sum, though.
How many 7-digit phone numbers can be formed if the first digit cannot be 0 and any digit can be repeated?
7
How many 4 digit palindromes are multiples of 9?
Nine. The sum of the digits must be a multiple of 9; because of the repeated digits, this is only possible if the first two digits add up to 9.
How many three digit combinations 000-999are there without repeating the same number twice?
999
