41 times 3 equals 123.
123 = (1 x 100) + (2 x 10) + (3 x 1)
15.375
Let x be the smallest number to be solved:x + (x+1) + (x+2) = 1233x + 3 = 1233x = 123 - 3 = 120x = 120 / 3 = 40 is the smallest numberand 40 + 41 + 42 = 123
well any multiple of 123 would be divisable by 123. Ex 123,246,369,492,615,738... but if your asking what 123 can be divided by its' 1 and itself, therefore making it a prime number 177
123 = 1 x 123, 3 x 41, 41 x 3, 123 x 1
1 x 123, 3 x 41, 41 x 3, 123 x 1
The prime factors of 123 are 3 and 41. 3 x 41 = 123
41 times 3 equals 123.
The factor pairs of 123 are 1 x 123 and 3 x 41
123 = 3 x 41
1 x 123, 3 x 41
1 x 123 3 x 41
3 x 41 = 123
The 4 factors of 123 are 1, 3, 41, and 123.The factor pairs of 123 are 1 x 123 and 3 x 41.The proper factors of 123 are 1, 3, and 41 or,if the definition you are using excludes 1, they are 3 and 41.The prime factors of 123 are 3 and 41.The distinct prime factors of 123 are, since there is no repetition of prime factors, also 3 and 41.The prime factorization of 123 are 3 x 41.
123 = (1 x 100) + (2 x 10) + (3 x 1)
3 x 41 = 123