78 hex=6 so 13x6=78
The number 78 fits your conditions. 26x3=78... and 13x6=78 !
To get the area of a rectangle, the formula is length times width, so 13x6= 78 inches.
Thirteen separte hexagons have 13x6 sides, or 78 sides. However, it's possible that they have shared borders, so then there would be fewer because you wouldn't count the same side twice if it was shared.
It actually depends if it's even or odd. So with odd numbers you take away one then divide by two then times it by the number you started with and you have your answer. I'll show you. e.g 13-1=12/2=6 13x6=78 With even numbers its almost the same thing but all you do is divide by two again and times by the number you started with and your answer is there. 22/2=11 22x11=242
The person receives 1 on the 1st day, 2 on the second, etc. So, you can group the numbers like this: (1+12)+(2+11)+(3+10)+(4+9)+(5+8)+(6+7) Then, the set in each parentheses equals 13. Since there's 6 parentheses sets, you can multiply 13x6=78.
6x0=0 7x0=0 8x0=0 9x0=0 10x0=0 11x0=0 12x0=0 13x0=0 6x1=6 7x1=7 8x1=8 9x1=9 10x1=10 11x1=11 12x1=12 13x1=13 6x2=12 7x2=14 8x2=16 9x2=18 10x2=20 11x2=22 12x2=24 13x2=26 6x3=18 7x3=21 8x3=24 9x3=27 10x3=30 11x3=33 12x3=36 13x3=39 6x4=24 7x4=28 8x4=32 9x4=36 10x4=40 11x4=44 12x4=48 13x4=52 6x5=30 7x5=35 8x8=40 9x5=45 10x5=50 11x5=55 12x5=60 13x5=65 6x6=36 7x6=42 8x6=48 9x6=54 10x6=60 11x6=66 12x6=72 13x6=78 6x7=42 7x7=49 8x7=56 9x7=63 10x7=70 11x7=77 12x7=84 13x7=91 6x8=48 7x8=56 8x8=64 9x8=72 10x8=80 11x8=88 12x8=96 13x8=104 6x9=54 7x9=63 8x9=72 9x9=81 10x9=90 11x9=99 12x9=108 13x9=117 6x10=60 7x10=70 8x10=80 9x10=90 10x10=100 11x10=110 12x10=120 13x10=130 6x11=66 7x11=77 8x11=88 9x11=99 10x11=110 11x11=121 12x11=132 13x11=143 6x12=72 7x12=84 8x12=96 9x12=108 10x12=120 11x12=132 12x12=144 13x12=156 6x13=78 7x13=91 8x13=104 9x13=117 10x13=130 11x13=143 12x13=156 13x13=169
Answer: There are 78 possible pairs in poker. Explained:If you have a group of four (the four suits) the are six combinations of two. There are 13 cards in a suit. 13X6=78. There are 78 possible pairs. Note: This is only true if you use one deck (if you use two there are 364) Alternate answer:There are 13 possible pairs in poker. Explained: There are 13 cards in each suit. Each pair is between two suits. there are 13 possible pairs Extra facts: There are 1378 groups of two in a deck of cards. There are 91 groups of two in each suit. To find the maximum number of groups of two in any number: the maximum number=Z (Z-1)+(Z-2)+(Z-3)+(Z-4)+(Z-5)etc. Ex: (3-1)+(3-2)+(3-3)=3 there are three possible combinations of all the (2) + (1) + (0)=3 numbers between 1 and 3 Ex2:(5-1)+(5-2)+(5-3)+(5-4)+(5-5)=10 (4) (3) (2) (1) (0) I am not a poker player but a mathimatician. You should be able to decide which of the first two answers is correct.