0
Add your answer:
Earn +20 pts
What is 56 in binary?
56 is 0011 1000 To convert between bases divide the number by the new base repeatedly until the whole number quotient is zero, noting the remainders in reverse order: 56 ÷ 2 = 28 r 0 28 ÷ 2 = 14 r 0 14 ÷ 2 = 7 r 0 7 ÷ 2 = 3 r 1 3 ÷ 2 = 1 r 1 1 ÷ 2 = 0 r 1 → 56 decimal in binary is 111000 (or 0011 1000 in 8 bits of a byte).
Prove that nCr plus nCr minus 1 equals n plus 1Cr?
nCr + nCr-1 = n!/[r!(n-r)!] + n!/[(r-1)!(n-r+1)!] = n!/[(r-1)!(n-r)!]*{1/r + 1/n-r+1} = n!/[(r-1)!(n-r)!]*{[(n-r+1) + r]/[r*(n-r+1)]} = n!/[(r-1)!(n-r)!]*{(n+1)/r*(n-r+1)]} = (n+1)!/[r!(n+1-r)!] = n+1Cr
What does the hexa number E78 in radix 7 with explanation?
E7816 = 14 x 256 + 7 x 16 + 8 = 370410 3704 ÷ 7 = 529 r 1 529 ÷ 7 = 75 r 4 75 ÷ 7 = 10 r 5 10 ÷ 7 = 1 r 3 1 ÷ 7 = 0 r 1 ⇒ 370410 = 135417 ⇒ E7816 = 135417 Alternatively, doing the arithmetic in hexadecimal: E7816 ÷ 716 = 21116 r 1 22116 ÷ 716 = 4B16 r 4 4B16 ÷ 716 = A16 r 5 A16 ÷ 716 = 116 r 3 116 ÷ 716 = 016 r 1 ⇒ E7816 = 135417
What is the quotient of 36 and 15480?
The answer is 43 r.0
How do i write a number r decreased by the quotient of a number r and two in an expression?
r/2-8
How do you write 1 minus the quotient of r and 7 in algebraic expression?
It is 1 - r/7
What is 1 minus the qoutient of r and 7?
42
Why does minus of minus equals plus?
The negative of a negative number is a positive number. The reason for this is that the first negative is a place holder for -1. When you have - - 4, that translates into -1 x -4. When you multiply two negative numbers, you get a positive.For example:- - 7 = -1 x -7 = 7- - r = -1 x -r = r
Have 2 digits divided by 7 remainder is 1 then halved the remainder is 1 one digit is 3 what number is it?
I think you're wanting a number of two digits, one of which is 3, that when divided by 7 gives a quotient and a remainder of 1 and when that quotient is divided by 2 it gives a remainder of 1: Answer: 36 36 ÷ 7 = 5 r 1 5 ÷ 2 = 2 r 1 If you want the number to be such that if it is divided by 7 the remainder is 1 and if it is divided by 2 the remainder is 1, then: Answer: 43 43 ÷ 7 = 6 r 1 43 ÷ 2 = 21 r 1
What is the answer to this math problem 3r squared minus 12r minus 15?
That factors to 3(r - 5)(r + 1) r = 5, -1
What is r in this equation and how do you do it minus 5 equals 7 plus 3r?
-5 = 7 + 3r | subtract 7 -12 = 3r | divide by 3 -4 = r
The quotient of 45 and r?
45÷r
How do you convert 85 into binary?
To convert from any base to another:Divide the number by the new base to get a quotient and a remainder.Note the remainder.If the quotient is zero stop as the remainder is the number in the new base.Divide the quotient by the new base to get a quotient and a remainder.Write the remainder in front of the previous remainder(s).Repeat from step 3.For example, to convert 8510 to octal (base 8):85 / 8 = 10 r 5 (answer so far: 5)10 / 8 = 1 r 2 (answer so far: 25)1 / 8 = 0 r 1 (answer so far: 125)quotient 0, so 8510 = 1258.To convert 8510 to binary:85 / 2 = 42 r 1 (answer so far: 1)42 / 2 = 21 r 0 (answer so far: 01)21 / 2 = 10 r 1 (answer so far: 101)10 / 2 = 5 r 0 (answer so far: 0101)5 / 2 = 2 r 1 (answer so far: 10101)2 / 2 = 1 r 0 (answer so far: 010101)1 / 2 = 0 r 1 (answer so far: 1010101)quotient 0, so 8510 = 10101012.
What is the quotient of 45 and r?
45/r
How do you Write the decimal number 2365 as a base 7 number?
Divide the number by the new base (7 in this case) to give a quotient (result) and remainder.Note the remainderMake the number the quotientIf the quotient is not zero repeat from step 1Write the remainders in reverse order (last found first)That's how I write a decimal number in any other base.This is me doing it for 2365 in to base 7:2365 ÷ 7 = 337 r 6337 ÷ 7 = 48 r 148 ÷ 7 = 6 r 66 ÷ 7 = 0 r 6⇒ 236510 = 66167
What is 56 in binary?
56 is 0011 1000 To convert between bases divide the number by the new base repeatedly until the whole number quotient is zero, noting the remainders in reverse order: 56 ÷ 2 = 28 r 0 28 ÷ 2 = 14 r 0 14 ÷ 2 = 7 r 0 7 ÷ 2 = 3 r 1 3 ÷ 2 = 1 r 1 1 ÷ 2 = 0 r 1 → 56 decimal in binary is 111000 (or 0011 1000 in 8 bits of a byte).
What are the factors of 11 and 7?
7's r 7& 1. 11's factorz r 11 & 1
