1+2+3.......+100 forms an ending arithmetic progression. There are two ways this can solved as follows-
1) the old an boring way of adding them up and getting an answer of 5050.
2)This step will involve the knowledge of Arithmetic Progressions. An AP is such a sequence of the numbers that each number will have common difference between it and its predecessor.
There is a certain formula given for solving the sum of the terms of an AP, which is
S=n(T+a)/2 where n is the number of terms of he AP, T is the final term and a is the first term. Putting the values-
S=100(100+1)/2= 50(101)= 5050.
Practically this method can be explained in this fashion- If you add one with 100, you get 101. Similarly 99+2= 101, 98+3=101.......till 50+51=100. We get 50 such pairs, therefore the sum os 50 into 101=5050
1+2+3...50+51......+98+99+100=(1+100)+(2+99)+(3+98)........+(50+51)=
(101)+(101)......50 times, therefore 1+.......100=50(101)=5050
1+2+3+4.....+100 = 101*50= 5050
5050
What is 100 divided by 2 plus 3
5,050
The sum of the numbers up to 100 is equal to (100 x 101)/2 = 5050
100% = 1 2 + 1 = 3 2 + 100% = 3
1+2+3+4.....+100 = 101*50= 5050
1 + 2 + 3 + 4 + 5 + 6 + 100 = 121
1 +100 = 101 100 - 1 = 99 99 +1 = 100 100 times 100 =10000 10000 divide by 2 = 5050Ans:5050
1 - 2 + 3 - 4 + 5 - 6 - 100 = 103
5050
Well, 1+1+1+2+3 equals 8, so 800.
505
1+2 = 3 1+2+3 = 6 1+2+3+4 = 10 1+2+...+ N = 1/2(N+1)N if N = 50, 1+2+...+50 = 1/2 x 51 x 50 = 1275 Since 2+4+6+...+100 = 2 x (1+2+3+...+50) = 2 x 1275 = 2550
5050 u noob
5050
What is 100 divided by 2 plus 3