20
Here is an example, radical 20 plus radical 5. Now radical 20 is 2(radical 5) so we can add radical 5 and 2 radical 5 and we have 3 radical 5.
If, by "3 radical 27" you mean the cuberoot of 27, the answer is YES. If you mean 3 times sqrt(27), the answer is NO.
20 times the square root of 2
sqrt(12)*sqrt(20) = sqrt(12*20) = sqrt(240) = sqrt(16*15) = sqrt(16)*sqrt(15) = 4*sqrt(15)
20
3
30
√18
Here is an example, radical 20 plus radical 5. Now radical 20 is 2(radical 5) so we can add radical 5 and 2 radical 5 and we have 3 radical 5.
radical (64/3) or 8/sqrt(3)
3 sqrt(6) x sqrt(6) = 18
First, note that radical 4 is 2. So 3xradical 4 is just 6, Now we have 6+2 radical 3. You can't do much with this except factor out a 2 if you want 2(3+Radical 3)
It can not be simplified any more. To the nearest hundredth, 6.71
If, by "3 radical 27" you mean the cuberoot of 27, the answer is YES. If you mean 3 times sqrt(27), the answer is NO.
The square root of 12 may be simplified to 2 times the square root of 3.
3 times the square root of 2