I would divide 5 into 245 by doubling 245 and then dividing by 10: 245 x 2 = 490 490 ÷ 10 = 49 ⇒ 5 divided into 245 is 49. To divide 5 into 245, the normal method is: Work from left to right: 5 doesn't go into 2 5 goes into 24 4 times, remainder 4 5 goes into 45 9 times. so 5 divided into 245 is 49. This would normally be written something like: ......... 49 .....------ . 5 | 245 ...... 20 ...... --- ........ 45 ........ 45 ........ --- .......... 0
2/245
40.8333
30.625
7.6562
49
I would divide 5 into 245 by doubling 245 and then dividing by 10: 245 x 2 = 490 490 ÷ 10 = 49 ⇒ 5 divided into 245 is 49. To divide 5 into 245, the normal method is: Work from left to right: 5 doesn't go into 2 5 goes into 24 4 times, remainder 4 5 goes into 45 9 times. so 5 divided into 245 is 49. This would normally be written something like: ......... 49 .....------ . 5 | 245 ...... 20 ...... --- ........ 45 ........ 45 ........ --- .......... 0
An infinite number of of multiples of 245 can be divided by 245.
No, it can also be divided by 5. Prime means its can only be divided by itself and 1.
245 divided by 6 is 40.83 or 40 with remainder 5.
40 divided 245 = 0.16326530612244897
sqrt(245)/sqrt(5) = sqrt(5) * sqrt(49) / sqrt(5) = sqrt(49) = 7
30.625
40.8333
2/245
40.8333
30.625