2628.866
9.7
32.3333
97.4444
Yes, 97 can be divided evenly only by 1 and 97 itself. This is because 97 is a prime number, which means it has only two factors: 1 and the number itself. Any attempt to divide 97 by any other number will result in a remainder, making it indivisible by any other whole number.
777 divided by 8 is 97.13 or 97 with remainder 1
2.732
1144.3299
97 divided by 10 is 9 with remainder 7.
19.4
97 divided by 5 is 19 with remainder 2
2.5052
9.7
67.9175
10.7778
10.7778
32.3333
This is an extremely poor question. There are 28 pairs of numbers and, in less than 10 minutes, I could find reasons why 17 pair were different from the other numbers in the set. A bit more time and I am sure I could do the rest. So here they are: 53 and 72: leave a remainder of 15 when divided by 19. 53 and 77: leave a remainder of 5 when divided by 12. 53 and 82: leave a remainder of 24 when divided by 29. 53 and 87: leave a remainder of 2 when divided by 17. 53 and 95: leave a remainder of 11 when divided by 21. 53 and 97: leave a remainder of 9 when divided by 11. 67 and 95: leave a remainder of 11 when divided by 28. 67 and 87: leave a remainder of 7 when divided by 17. 67 and 97: leave a remainder of 7 when divided by 30. 72 and 82: leave a remainder of 0 when divided by 2 (are even). 72 and 87: leave a remainder of 0 when divided by 3 (multiples of 3). 72 and 95: leave a remainder of 3 when divided by 23. 72 and 97: leave a remainder of 22 when divided by 25. 77 and 95: leave a remainder of 5 when divided by 9. 77 and 97: leave a remainder of 17 when divided by 20. 82 and 95: leave a remainder of 4 when divided by 13. 87 and 95: leave a remainder of 7 when divided by 8.