n = 4
25 x n = 25 x 4
25n = 100
.25 N 25N/100 1/4 N i think this is write im only in gr8.
25n
10 + 25n, where n is an integer.
When n = 4, 3n = 3*4 = 12
24.
19
.25 N 25N/100 1/4 N i think this is write im only in gr8.
25n
125
25n
10 + 25n, where n is an integer.
-4
.25n + .5n + 18 = n.75n - n = -18-.25n = -18.25n = 18n = 72
n=1 is the the lowest level there is.
if n=4 then n+1 would be 4+1 which equals 5
N= 5.5
To find the smallest number of terms in the arithmetic progression (AP) 325, 350, 375, ..., we first identify the first term ( a = 325 ) and the common difference ( d = 25 ). The ( n )-th term of the AP can be expressed as ( a_n = 325 + (n-1) \cdot 25 = 325 + 25n - 25 = 300 + 25n ). The sum ( S_n ) of the first ( n ) terms is given by ( S_n = \frac{n}{2} \cdot (a + a_n) = \frac{n}{2} \cdot (325 + (300 + 25n)) = \frac{n}{2} \cdot (625 + 25n) = \frac{25n^2 + 625n}{2} ). Setting this greater than 10,000 and solving for ( n ) gives ( n^2 + 25n - 800 > 0 ), leading to ( n \geq 25 ). Thus, a minimum of 25 terms is required for the sum to exceed 10,000.