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What is the Prime factorization of 2001?
3 x 23 x 29
2x equals 12 X-5y equals 29?
Answer : x = 6 : y = -4.62x = 12 therefore x = 6 : substituting in x - 5y = 29 gives :-6 - 5y = 29 : 5y = 6 - 29 = -23 : y = -23/5 : y = - 4.6
What are the two numbers if the sum is 29 and the difference between the number is 17?
The two numbers are 23 and 6. Let: x = first number y = second number x + y = 29 (Equation 1) x - y = 17 x = 17 + y (Equation 2) Substitute Eq. (2) in Eq. (1): x + y = 29 (17 + y) + y = 29 17 + 2y = 29 17 -17 + 2y = 29 - 17 2y = 12 2y/2 = 12/2 y = 6 - second number x = 17 + y x = 17 + 6 x = 23 - first number check. 23 - 6 = 17 17 = 17 Therefore, the two numbers are 23 and 6.
Write 2001 as a product of primes?
To find the product of primes, or lowest terms, just divide 2001 as many times as possible. 2001 divided by 3 is 667 667 divided by 23 is 29 3, 23, and 29 are all prime numbers, so 2001 written as a product of primes is 3 x 23 x 29
What two numbers multiply into 87?
29 times 3 equals 87
