3 x 23 x 29
Answer : x = 6 : y = -4.62x = 12 therefore x = 6 : substituting in x - 5y = 29 gives :-6 - 5y = 29 : 5y = 6 - 29 = -23 : y = -23/5 : y = - 4.6
The two numbers are 23 and 6. Let: x = first number y = second number x + y = 29 (Equation 1) x - y = 17 x = 17 + y (Equation 2) Substitute Eq. (2) in Eq. (1): x + y = 29 (17 + y) + y = 29 17 + 2y = 29 17 -17 + 2y = 29 - 17 2y = 12 2y/2 = 12/2 y = 6 - second number x = 17 + y x = 17 + 6 x = 23 - first number check. 23 - 6 = 17 17 = 17 Therefore, the two numbers are 23 and 6.
To find the product of primes, or lowest terms, just divide 2001 as many times as possible. 2001 divided by 3 is 667 667 divided by 23 is 29 3, 23, and 29 are all prime numbers, so 2001 written as a product of primes is 3 x 23 x 29
29 times 3 equals 87
1 x 667, 23 x 29, 29 x 23, 667 x 1 = 667
29 x 23 = 667
2001 = 3 x 23 x 29
3 x 23 x 29
Assuming that by expressing that equation as a question you're looking to solve for x: x2 - 4x - 29 = -10 x2 - 4x + 4 = 23 (x - 2)2 = 23 x - 2 = ± √23 x = 2 ± √23
Answer : x = 6 : y = -4.62x = 12 therefore x = 6 : substituting in x - 5y = 29 gives :-6 - 5y = 29 : 5y = 6 - 29 = -23 : y = -23/5 : y = - 4.6
2001 = 3 x 23 x 29
the answer is x=23, y=-6, found by the equations x+y=17 and x-y=29, so y=17-x, thus x-(17-x)=29, then 2x=46, x=23, so y=17-23=-6
The only common factor of 23 and 29 is 1.23 = 1 x 2329 = 1 x 29It is 1 because both numbers are primes
2,001 = 3 x 23 x 29
79 x 23
In the future please be more specific as to what you are asking. Factoring: 2 x 2 x 2 x 29 In other terms: 23 x 29 or 8 x 29